Answered: An alpha particle (q = +2e, m = 4.00 u)… | bartleby

Related questions

Question

An alpha particle (q = +2e, m = 4.00 u) travels in a circular path of radius 6.05 cm in a uniform magnetic field with B = 1.50 T. Calculate
(a) its speed, (b) its period of revolution, (c) its kinetic energy, and (d) the potential difference through which it would have to be
accelerated to achieve this energy.
(a) Number
i
Units
(b) Number
Units
(c) Number
i
Units
(d) Number
i
Units

Expert Solution

Trending now

This is a popular solution!

Step by step

Solved in 2 steps with 2 images

SEE SOLUTION Check out a sample Q&A here

Blurred answer

Similar questions

An alpha-particle (m = 6.64·10−27 kg; q = 3.2·10−19 C) travels in a circular path of radius 28 cm in a uniform magnetic field of magnitude 1.3 T. (a) What is the speed of the particle? (b) What is the kinetic energy in electron-volts? (c) Through what potential difference must the particle be accelerated in order to give it this kinetic energy?
In a nuclear experiment a proton with kinetic energy 0.94 MeV moves in a circular path in a uniform magnetic field. What energy must (a) an alpha particle (q = +2e, m = 4.0 u) and (b) a deuteron (q = +e, m = 2.0 u) have if they are to circulate in the same circular path?
What uniform magnetic field, applied perpendicular to a beam of electrons moving at 2.70 ✕ 106 m/s, is required to make the electrons travel in a circular arc of radius 0.400 m?
Alpha particles (mass = 6.7 × 10^-27 kg, q = +2e) are accelerated from rest through a potential difference of 3.0 kV. They then enter a uniform magnetic field B = 0.40 T perpendicular to their direction of motion. Calculate the radius of their path. Problem in photo.
At what speed (in m/s) will a proton move in a circular path of the same radius as an electron that travels at 8.39 ✕ 105 m/s perpendicular to the Earth's magnetic field at an altitude where the field strength (B) is 1.37 ✕ 10−4 T? (Hint: First calculate the radius of circular path of an electron and use it to calculate the speed of proton) me=9.109*10-31, mp=1.67*10-27, q=1.602*10-19
An alpha particle (q - +2e, m = 4.00 u) travels in a circular path of radius 4.79 cm in a uniform magnetic field with B- 1.06 T. Calculate (a) its speed, (b) its period of revolution, (c) its kinetic energy, and (d) the potential difference through which it would have to be accelerated to achieve this energy. (a) Number i Units (b) Number i Units (c) Number i Units (d) Number Units
Atom 1 of mass 35 u and atom 2 of mass 37 u are both singly ionized with a charge of +e. After being introduced into a mass spectrometer (see the figure below) and accelerated from rest through a potential difference V = 7.5 kV, each ion follows a circular path in a uniform magnetic field of magnitude B = 0.30 T. What is Δx, the distance between the points where the ions strike the detector?