**Problem Description:**An airplane flies eastward and always accelerates at a constant rate. At one position along its path, it has a velocity of 26.7 m/s. It then flies a further distance of 42500 m, and afterwards, its velocity is 42.3 m/s. Find the airplane's acceleration.**Solution:**To find the acceleration of the airplane, we can use the formula for constant acceleration:\[ v_f^2 = v_i^2 + 2a \cdot d \]Where:- \( v_f \) = final velocity = 42.3 m/s- \( v_i \) = initial velocity = 26.7 m/s- \( a \) = acceleration- \( d \) = distance = 42500 m**Calculate Acceleration:**\[42.3^2 = 26.7^2 + 2a \cdot 42500 \]**Acceleration:**\[ a = \ldots \] m/s\(^2\)**Calculate Elapsed Time:**To calculate how much time elapses while the airplane covers the distance of 42500 m, we use the formula:\[ v_f = v_i + a \cdot t \]Where:- \( t \) = timeSolve for \( t \) once acceleration is known.**Elapsed Time:**\[ t = \ldots \] s

Given value--- Initial velocity = 26.7 m/s. distance = 42500 m. final velocity = 42.3 m/s. We have…

An airplane flies eastward and always accelerates at a constant rate. At one position along its path, it has a velocity of 26.7 It then flies a further distance of 42500 m, and afterwards, its velocity is 42.3 m/s. Find the airplane's acceleration. acceleration: Calculate how much time elapses while the airplane covers those 42500 m. elapsed time:

An airplane flies eastward and always accelerates at a constant rate. At one position along its path, it has a velocity of 26.7 It then flies a further distance of 42500 m, and afterwards, its velocity is 42.3 m/s. Find the airplane's acceleration. acceleration: Calculate how much time elapses while the airplane covers those 42500 m. elapsed time:

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

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Concept explainers

Distance and Speed

The speed, distance and time relation forms the basis of study of motion. You will need these concepts in the study of Mechanics. This concept is applicable for students who are studying the following courses –

Question

**Problem Description:**

An airplane flies eastward and always accelerates at a constant rate. At one position along its path, it has a velocity of 26.7 m/s. It then flies a further distance of 42500 m, and afterwards, its velocity is 42.3 m/s. Find the airplane's acceleration.

**Solution:**

To find the acceleration of the airplane, we can use the formula for constant acceleration:

\[ v_f^2 = v_i^2 + 2a \cdot d \]

Where:
- \( v_f \) = final velocity = 42.3 m/s
- \( v_i \) = initial velocity = 26.7 m/s
- \( a \) = acceleration
- \( d \) = distance = 42500 m

**Calculate Acceleration:**

\[
42.3^2 = 26.7^2 + 2a \cdot 42500
\]

**Acceleration:**

\[ a = \ldots \] m/s\(^2\)

**Calculate Elapsed Time:**

To calculate how much time elapses while the airplane covers the distance of 42500 m, we use the formula:

\[ v_f = v_i + a \cdot t \]

Where:
- \( t \) = time

Solve for \( t \) once acceleration is known.

**Elapsed Time:**

\[ t = \ldots \] s

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