An aircraft emergency locator transmitter (ELT) is a device designed to transmit a signal in the case of a crash. The Altigauge Manufacturing Company makes 80% of the ELTS, the Bryant Company makes 15% of them, and the Chartair Company makes the other 5%. The ELTS made by Altigauge have a 4% rate of defects, the Bryant ELTS have a 6% rate of defects, and the Chartair ELTs have a 9% rate of defects (which helps to explain why Chartair has the lowest market share). a. If an ELT is randomly selected from the general population of all ELTS, find the probability that it was made by the Altigauge Manufacturing Company. b. If a randomly selected ELT is then tested and is found to be defective, find the probability that it was made by the Altigauge Manufacturing Company * Please Only Give a Screenshot of your Online Code & Result. Please Do Not Give Typed Text. I will make sure to give a Thumbs Up, if u can do this. Thank you.

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Hello. Please create a Python Program that solves the following question on Probability (Answer to question is in the other Pic). Please Only Give a Screenshot of your Online Code & Result. Please Do Not Give Typed Text. 
* If you can do this, I will definitely give you a thumbs up. Thank you!

Python Homework #1 - Baye's Theorem
Question - Make a Python Program That Solves the Following
Probability Problem (Answer to Problem in next picture):
An aircraft emergency locator transmitter (ELT) is a device designed
to transmit a signal in the case of a crash. The Altigauge
Manufacturing Company makes 80% of the ELTS, the Bryant
Company makes 15% of them, and the Chartair Company makes the
other 5%. The ELTs made by Altigauge have a 4% rate of defects, the
Bryant ELTs have a 6% rate of defects, and the Chartair ELTs have a
9% rate of defects (which helps to explain why Chartair has the lowest
market share).
a. If an ELT is randomly selected from the general population of
all ELTS, find the probability that it was made by the Altigauge
Manufacturing Company.
b. If a randomly selected ELT is then tested and is found to be
defective, find the probability that it was made by the Altigauge
Manufacturing Company
* Please Only Give a Screenshot of your Online Code & Result.
Please Do Not Give Typed Text. I will make sure to give a
Thumbs Up, if u can do this. Thank you.
Transcribed Image Text:Python Homework #1 - Baye's Theorem Question - Make a Python Program That Solves the Following Probability Problem (Answer to Problem in next picture): An aircraft emergency locator transmitter (ELT) is a device designed to transmit a signal in the case of a crash. The Altigauge Manufacturing Company makes 80% of the ELTS, the Bryant Company makes 15% of them, and the Chartair Company makes the other 5%. The ELTs made by Altigauge have a 4% rate of defects, the Bryant ELTs have a 6% rate of defects, and the Chartair ELTs have a 9% rate of defects (which helps to explain why Chartair has the lowest market share). a. If an ELT is randomly selected from the general population of all ELTS, find the probability that it was made by the Altigauge Manufacturing Company. b. If a randomly selected ELT is then tested and is found to be defective, find the probability that it was made by the Altigauge Manufacturing Company * Please Only Give a Screenshot of your Online Code & Result. Please Do Not Give Typed Text. I will make sure to give a Thumbs Up, if u can do this. Thank you.
#8. (@.) P(A) – probability that, an ELT was made by Altigauge - 80/=0.8
P (*)
B. Probability that defective ELT was made by Altigauge
P(P) =1= made by Bryant Company 157.
made
1.
mình sang tachiba
Chartair Company Sh Jodard (w
54
PCC)=1=
P(c)
D: defected.
P(A) - probability that an ELT made by Attigauge is defective 47. =004
(
Bryant Company is defectives / = 0.06
Charteur Company is clefective 97.=0.09.
P (B) = 11 =
P (2) = 1/2
Find P (£) = P(A).
P(A)
P()- total of defective ELT
P(D)= P(2). P(A) + P(B) · P(B) + P(Ⓡ) · P(C) = (0.04. 0.80)+ (0.06 0.15)+(009,
= 0.0455
P (A) = 0.8.0.04
0.0455
0-032
0.0455
2
0.703 70.36
Transcribed Image Text:#8. (@.) P(A) – probability that, an ELT was made by Altigauge - 80/=0.8 P (*) B. Probability that defective ELT was made by Altigauge P(P) =1= made by Bryant Company 157. made 1. mình sang tachiba Chartair Company Sh Jodard (w 54 PCC)=1= P(c) D: defected. P(A) - probability that an ELT made by Attigauge is defective 47. =004 ( Bryant Company is defectives / = 0.06 Charteur Company is clefective 97.=0.09. P (B) = 11 = P (2) = 1/2 Find P (£) = P(A). P(A) P()- total of defective ELT P(D)= P(2). P(A) + P(B) · P(B) + P(Ⓡ) · P(C) = (0.04. 0.80)+ (0.06 0.15)+(009, = 0.0455 P (A) = 0.8.0.04 0.0455 0-032 0.0455 2 0.703 70.36
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