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An air-standard cycle with constant specific heats at room temperature is executed in a closed system with 0.003 kg of air and consists of the following three processes: 1-2 v= Constant heat addition from 95 kPa and 17°C to 380 kPa 2-3 Isentropic expansion to 95 kPa 3-1 P=Constant heat rejection to initial state The properties of air at room temperature are cp=1.005 kJ/kg-K, cv=0.718 kJ/kg-K, and k=1.4.

An air-standard cycle with constant specific heats at room temperature is executed in a closed system with 0.003 kg of air and consists of the following three processes: 1-2 v= Constant heat addition from 95 kPa and 17°C to 380 kPa 2-3 Isentropic expansion to 95 kPa 3-1 P=Constant heat rejection to initial state The properties of air at room temperature are cp=1.005 kJ/kg-K, cv=0.718 kJ/kg-K, and k=1.4.

Elements Of Electromagnetics
Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
ChapterMA: Math Assessment
Section: Chapter Questions
Problem 1.1MA
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**Required information** **Problem 09.015 - 3-Step Air-Standard Cycle with Constant Specific Heats - DEPENDENT MULTI-PART PROBLEM - ASSIGN ALL PARTS** An air-standard cycle with constant specific heats at room temperature is executed in a closed system with 0.003 kg of air and consists of the following three processes: - 1–2 v = Constant heat addition from 95 kPa and 17°C to 380 kPa - 2–3 Isentropic expansion to 95 kPa - 3–1 P = Constant heat rejection to initial state The properties of air at room temperature are: - \( c_p = 1.005 \, \text{kJ/kg⋅K} \) - \( c_v = 0.718 \, \text{kJ/kg⋅K} \) - \( k = 1.4 \) --- **Problem 09.015.b - Net Work for Constant Heat Capacity Air-Standard Cycle** Calculate the net work per cycle, in kJ. (You must provide an answer before moving on to the next part.) The net work per cycle is \_\_\_\_ kJ.
Transcribed Image Text:**Required information** **Problem 09.015 - 3-Step Air-Standard Cycle with Constant Specific Heats - DEPENDENT MULTI-PART PROBLEM - ASSIGN ALL PARTS** An air-standard cycle with constant specific heats at room temperature is executed in a closed system with 0.003 kg of air and consists of the following three processes: - 1–2 v = Constant heat addition from 95 kPa and 17°C to 380 kPa - 2–3 Isentropic expansion to 95 kPa - 3–1 P = Constant heat rejection to initial state The properties of air at room temperature are: - \( c_p = 1.005 \, \text{kJ/kg⋅K} \) - \( c_v = 0.718 \, \text{kJ/kg⋅K} \) - \( k = 1.4 \) --- **Problem 09.015.b - Net Work for Constant Heat Capacity Air-Standard Cycle** Calculate the net work per cycle, in kJ. (You must provide an answer before moving on to the next part.) The net work per cycle is \_\_\_\_ kJ.
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