Answered: An air-gap parallel-plate capacitor has… | bartleby

Related questions

Question

An air-gap parallel-plate capacitor has a plate area of 2 cm2 and a separation of 3 mm is charged to 2 V. Take epsilon0=8.854x10^-12.The charge of this capacitor is:

a.

1.77 pC

b.

4.72 pC

c.

0.443 pC

d.

3.54 pC

e.

0.885 pC

f.

2.02 pC

g.

0.506 pC

h.

1.18 pC

Expert Solution

Trending now

This is a popular solution!

Step by step

Solved in 2 steps

SEE SOLUTION Check out a sample Q&A here

Blurred answer

Similar questions

How much kinetic energy does an electron lose when it goes from point a to point b if the voltage difference between these two points is 50 V and is slowing it down? a. 50 eV b. 50 V c. 1.60 x 10^-19 V d. 1.60 x 10^-19 J e. None of the above
Four capacitors are connected as shown. (a) Find the equivalent capacitance between points a and b. (b) Calculate the charge on each capacitor, taking ΔVab = 15.0 V.
What is the electric charge, in the unit of μC, stored in a capacitor with C = 42 μF if the voltage across the capacitor is 1.6 V
How much energy is stored in a 56 pF capacitor that has been charged to 12 V? Convert your answer to eV. O 2.5 x 10^10 eV O 4.6 x 10^8 eV 3.8 x 10^9 eV 6.1 x 10^10 eV 8.3 x 10^8 eV
A parallel plate capacitor has a charge on one plate of q = 1.1E-06 C. Each square plate is d1 = 1.9 cm wide and the plates of the capacitor are separated by d2 = 0.65 mm. The gap is filled with air, εo = 8.85 × 10-12 C2/Nm2. What is the voltage between the plates, ΔV, in V?
A 0.40-μF capacitor is connected to a 6.5-V battery. How much charge is on each plate of the capacitor? Express your answer using two significant figures.
Consider a parallel-plate capacitor with some non-zero charge on the plates. If we double the charge surface density on each of the plates and double the separation between the plates, how does the energy density of the capacitor change? A. The energy density stays the same. B. The energy density is halved. C. The energy density decreases by a factor of 2–√. D. The energy density increases by a factor of 4. E. The energy density increases by a factor of 2–√.
The magnitude of the charge moving between the plates is | q | = 10 µC. The voltage between the plates is 15 V, and the electric field between the capacitor plates is 70 N/C. When charge q crossed from the top to the bottom plate how much kinetic energy in Joules does it gain? a. 7.0e-4 J b. 150 J c. 1.5e-4 J d. 42.0 J
Question 3 and 4
A parallel-plate capacitor has square plates of side length s and distance d between them. It stores energy U when it is connected across a fixed potential difference V. In order to decrease by a factor of 4 the amount of energy stored in this capacity will still connected to the potential difference V, the lengths that should be changed to...? A. 4s B. S/2 C. 8s D. 2s E. S/4
You measure the voltage across two parallel capacitors to be 38 V. If they have a separation distance 0f 3.5 mm, what is the strength of the electric field in N/C? a. 1.09 x 10^4 N/C b. 1.33 x 10^4 N/C c. 9.21 x 10^-5 N/C d. 722 N/C e. None of the above
A charged capacitor stores 10C at 40V .Its stored energy is: Select one: a. 400 J b. 2.5 J c. 0.2 J d. 200 J e. 4 J

SEE MORE QUESTIONS