An air-filled capacitor consists of two parallel plates, each with an area of 7.60 cm2, separated by a distance of 2.20 mm. A 19.0-V potential difference is applied to these plates. (a) Calculate the electric field between the plates. 8.63 kV/m (b) Calculate the surface charge density. 7.64e-8 |× nC/m2 (c) Calculate the capacitance. 3.058e-12 x pF
An air-filled capacitor consists of two parallel plates, each with an area of 7.60 cm2, separated by a distance of 2.20 mm. A 19.0-V potential difference is applied to these plates. (a) Calculate the electric field between the plates. 8.63 kV/m (b) Calculate the surface charge density. 7.64e-8 |× nC/m2 (c) Calculate the capacitance. 3.058e-12 x pF
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
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![An air-filled capacitor consists of two parallel plates, each with an area of 7.60 cm2, separated by a distance of 2.20 mm. A 19.0-V potential difference is applied to these plates.
(a) Calculate the electric field between the plates.
8.63
V kV/m
(b) Calculate the surface charge density.
7.64e-8
x nc/m?
(c) Calculate the capacitance.
3.058e-12
X pF
(d) Calculate the charge on each plate.
5.8e-11
X pC](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F8bc50567-c228-4f0f-97d7-a79b04b90de6%2F53b0ee41-a060-460f-864d-93aee768f69d%2Fu6erovb_processed.jpeg&w=3840&q=75)
Transcribed Image Text:An air-filled capacitor consists of two parallel plates, each with an area of 7.60 cm2, separated by a distance of 2.20 mm. A 19.0-V potential difference is applied to these plates.
(a) Calculate the electric field between the plates.
8.63
V kV/m
(b) Calculate the surface charge density.
7.64e-8
x nc/m?
(c) Calculate the capacitance.
3.058e-12
X pF
(d) Calculate the charge on each plate.
5.8e-11
X pC
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