An air-conditioning unit is fastened to a roof that slopes at an angle of 0 = 33° above the horizontal (Figure 1). Its weight is a force F on the air conditioner that is directed vertically downward. In order that the unit not crush the roof tiles, the component of the unit's weight perpendicular to the roof cannot exceed 425 N. (One newton, or 1 N, is the Sl unit of force. It is equal to 0.2248 lb.) (a) What is the maximum allowed weight of the unit? (b) If the fasteners fail, the unit slides L= 1.60 m along the roof before it comes to a halt against a ledge. How much work does the weight force do on the unit during its slide if the unit has the weight calculated in part (a)? The work done by a force on an object that undergoes a displacement 5 is W = F.5.
An air-conditioning unit is fastened to a roof that slopes at an angle of 0 = 33° above the horizontal (Figure 1). Its weight is a force F on the air conditioner that is directed vertically downward. In order that the unit not crush the roof tiles, the component of the unit's weight perpendicular to the roof cannot exceed 425 N. (One newton, or 1 N, is the Sl unit of force. It is equal to 0.2248 lb.) (a) What is the maximum allowed weight of the unit? (b) If the fasteners fail, the unit slides L= 1.60 m along the roof before it comes to a halt against a ledge. How much work does the weight force do on the unit during its slide if the unit has the weight calculated in part (a)? The work done by a force on an object that undergoes a displacement 5 is W = F.5.
College Physics
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Author:Raymond A. Serway, Chris Vuille
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Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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An air-conditioning unit is fastened to a roof that slopes at
an angle of 0 = 33° above the horizontal (Figure 1). Its
weight is a force F on the air conditioner that is directed
vertically downward. In order that the unit not crush the
roof tiles, the component of the unit's weight
perpendicular to the roof cannot exceed 425 N. (One
newton, or 1 N, is the Sl unit of force. It is equal to
0.2248 lb.) (a) What is the maximum allowed weight of
the unit? (b) If the fasteners fail, the unit slides
L = 1.60 m along the roof before it comes to a halt
against a ledge. How much work does the weight force
do on the unit during its slide if the unit has the weight
Use the relationship between the magnitude and direction of a vector and its components to solve
for the target variable in question (a).
Express your answer with the appropriate units.
> View Available Hint(s)
?
F =
Value
Units
calculated in part (a)? The work done by a force F on an
object that undergoes a displacement š is W = F.3.
Submit
Figure
< 1 of 1>
Part F
Use the definition of the scalar product to solve for the target variable in question (b).
Express your answer with the appropriate units.
> View Available Hint(s)
HẢ
W =
Value
Units
Submit
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