An air conditioner cools humid air at temperature t₁ = 25°C and relative humidity 1 = 70% to temperature t2 = 10°C. Determine the final relative humidity, 92, and calculate the following (show all working): i. ii. the energy that is removed; the water mass extracted from the air.
An air conditioner cools humid air at temperature t₁ = 25°C and relative humidity 1 = 70% to temperature t2 = 10°C. Determine the final relative humidity, 92, and calculate the following (show all working): i. ii. the energy that is removed; the water mass extracted from the air.
Chapter2: Loads On Structures
Section: Chapter Questions
Problem 1P
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Transcribed Image Text:An air conditioner cools humid air at temperature t₁ = 25°C and
relative humidity 1 = 70% to temperature t2 = 10°C.
Determine the final relative humidity, 2, and calculate the following
(show all working):
i.
ii.
the energy that is removed;
the water mass extracted from the air.
Transcribed Image Text:05
-06
-0-7
-0-7
08
09 Sensible/total heat
10 ratio for water
0-9
added at 30 C
-08
-06
05
04
0.75
02
-10
01 0
25
-10
30
pe
Based on a barometric
pressure of 101-325 kPa
0-80
Specific enthalpy/(kJ-kg-¹)
45
S5 09
10
09
10
65
15
70
15
80
Specific volume/ m³ kg-¹
0.85
Wet-bulb temperature/"C (sling)
10
20
peep
20
15
95
25.
25
100
20
105
OLL
90
90 80
30
Dry-bulb temperature/C
35
120
25
Specific enthalpy/(kJ-kg-¹)
30
70
125
60
40
35
130
Percentage saturation/%
50
40
45
40
45
135
50
30
50
140
55
55
20
-0.030
-0-029
-0-028
-0-027
-0-026
-0-025
-0-024
-0.023
-0.022
-0021
-0-020
-0.019
+0018
60
0017
-0.016
4-0015
0014
0013
-0.012
0011
-0.010
-0.009
-0.008
+0.007
-0.006
-0.005
+0.004
-0-003
-0.002
-0.001
-0.000
(kg kg dry air)
Moisture co
60
8
8
Specific enthalpy / (kJ-kg-¹)
65
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