An advertising executive wants to estimate the mean weekly amount of time consumers spend watching traditional television daily. Based on previous studies, the standard deviation is assumed to be 18 minutes. The executive wants to estimate, with 99%confidence, the mean weekly amount of time to within +6 minutes.a. What sample size is needed?b. If 95% confidence is desired, how many consumers need to be selected?a. The sample size required for 99% confidence is.(Round up to the nearest integer.)

Answered: Image /qna-images/answer/a65a442f-fb55-46c5-a3a5-d1e1beee20cf.jpg

Answered: An advertising executive wants to…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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The average McDonald's restaurant generates $3.6 million in sales each year with a standard deviation of 0.9. Trent wants to know if the average sales generated by McDonald's restaurants in Kentucky is different than the worldwide average. He surveys 27 restaurants in Kentucky and finds the following data (in millions of dollars): 4.1, 2.8, 4.4, 4.5, 5.3, 5, 3.7, 2.9, 3.8, 4.8, 3.6, 2.3, 3.7, 2.9, 2.9, 4, 1.1, 5.2, 2.9, 5, 4, 4, 5.9, 3.2, 2.2, 4.3, 3.8 Perform a hypothesis test using a 3% level of significance. Step 1: State the null and alternative hypotheses. Ho: [? v] ? v На: ? ? v (So we will be performing a Select an answer test.) Step 2: Assuming the null hypothesis is true, determine the features of the distribution of point estimates using the Central Limit Theorem. By the Central Limit Theorem, we know that the point estimates are Select an answer v with distribution mean and distribution standard deviation Step 3: Find the p-value of the point estimate. P( ? v ? v = P( ? ♥ ?…
According to one study, brain weights of men are normally distributed with a mean of 1.10 kg and a standard deviation of 0.12 kg. Use the data to answer parts (a) through (e). Click here to view page 1 of the table of areas under the standard normal curve. Click here to view page 2 of the table of areas under the standard normal curve. a. Determine the sampling distribution of the sample mean for samples of size 3. Interpret your answer in terms of the distribution of all possible sample mean brain weights for samples of three men. The mean of the sample mean is µ, kg. (Type an integer or a decimal. Do not round.) The standard deviation of the sample mean is o, = kg. (Round to four decimal places as needed.) Interpret these answers in context. For the brain weights have a normal distribution with a mean of kg and a standard deviation of kg. (Type integers or decimals rounded to four decimal places as needed.) b. Repeat part (a) for samples of size 12. The mean of the sample mean is µ;…
A standardized memory test has a mean of u = 10p and a standard deviation of ó = 10. Answer the following questions: A. What proportion of people would score below 88 on the memory test? B. What is the percentile rank for someone who scored a 116 on the memory test? C. What are the scores that separate the middle 30% (15% each side of the mean) D. What percent of individuals would score between 86 and 109?
Suppose the durations of human pregnancies follow a mound-shaped distribution with a mean of 266 days and a standard deviation of 18 days. a. Approximately what percentage of human pregnancies last between 248 and 284 days? b. Between what two values will the durations of 95% of all human pregnancies fall? Answer in days
1. According to one study, the average hours of sleep on a weeknight for men was 6.9 hours with a standard deviation of 1.5 hours. a. Find the proportion of men who sleep for more than 8 hours per night. b. Find the proportion of men who sleep for less than 6 hours per night. c. Find the proportion of men who sleep between 6-8 hours per night. d. Find the number of hours that represents the 90th percentile.
The p hat =0.25, proportion standard deviation=0.065, and z=1.960. 34. What is the size of the sampling proportion?* A. small B. large C. both small and large D. cannot be determined
If your target population is 123, how many samples do you need for a sampling error of .05 and a level of confidence of 95 percent (.05 level)? Show your solution.
1. The EPA fuel economy estimates for automobile models tested recently predicted a mean of 24.8 mpg and a standard deviation of 6.2 mpg for highway driving. a. About what percent of cars get less than 31 mpg? b. What percent of cars get more than 20 mpg? c. What percent of cars get between 22 and 30 mpg? d. What gas mileage represents the 75th percentile? e. What gas mileages separate the bottom 3% and top 3% of cars? X
Six different titrations are found to be 0.5018 0.5047 0.5062 0.5039 0.5056 0.5038. Calculate the mean, median, average deviation, standard deviation, and coefficient of variation
A. Find the sample meanB. Find the sample standard deviation C. Construct a 98% confidence interval for the population mean(please show what numbers you are putting into the formula for part b)

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