Can you explain for me the same method but by your self because I did not understand ot well An ac equivalent circuit of a Darlington pair configuration is shown in Fig-ure P6.79. The transistor parameters are B, = 120, B = 80, V = 80 V.and V42 = 50 V. Determine the output resistance R.Ic: = IBias = I mA: (b) lcz = I mA. IBias = 0.2 mA; and (c) Ic = 2 mA.IBiss = 0.Q. 3for(a)-R.aAC groundFigure P6.79是)12012180Imı: 38.62 m AN , rm,:3-1o8 Kn,Yo,: 79-68 Kr9m2 - 3 8. 46 mn AV rilz=2.08 Kn , ľo̟ : 50KAVg - VT.KULYo,2) Vn, +VM,:0 -) Va, : -Vn,• KCI at hThen3 Vn2 - -V r,+12a folluwbe hamalpageitvq (o.00031825G°79.68-38 62)- Vg(0.32495)79-68%3D- 30 77Kn

It is given that: β1 = 120, β2 = 80, VA1 = 80 V, and VA2 = 50 V

An ac equivalent circuit of a Darlington pair configuration is shown in Fig- ure P6.79. The transistor parameters are B, = 120, B, = 80, V = 80 V. and Va2 = 50 V. Determine the output resistance R. for (a) Icz = Ipias =I mA: (b) lc2 = 1 Inias = 0. I mA. Inas = 0.2 mA; and (c) Ic2 = 2 mA.

An ac equivalent circuit of a Darlington pair configuration is shown in Fig- ure P6.79. The transistor parameters are B, = 120, B, = 80, V = 80 V. and Va2 = 50 V. Determine the output resistance R. for (a) Icz = Ipias =I mA: (b) lc2 = 1 Inias = 0. I mA. Inas = 0.2 mA; and (c) Ic2 = 2 mA.

Introductory Circuit Analysis (13th Edition)

13th Edition

ISBN:9780133923605

Author:Robert L. Boylestad

Publisher:Robert L. Boylestad

Chapter1: Introduction

Section: Chapter Questions

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Question

100%

Can you explain for me the same method but by your self because I did not understand ot well

An ac equivalent circuit of a Darlington pair configuration is shown in Fig-
ure P6.79. The transistor parameters are B, = 120, B = 80, V = 80 V.
and V42 = 50 V. Determine the output resistance R.
Ic: = IBias = I mA: (b) lcz = I mA. IBias = 0.2 mA; and (c) Ic = 2 mA.
IBiss = 0.
Q. 3
for
(a)
-R.
a
AC ground
Figure P6.79
是)
120
121
80
Imı: 38.62 m AN , rm,:3-1o8 Kn,Yo,: 79-68 Kr
9m2 - 3 8. 46 mn AV rilz=2.08 Kn , ľo̟ : 50KA
Vg - VT
.KUL
Yo,
2) Vn, +VM,:0 -) Va, : -Vn,
• KCI at h
Then
3 Vn2 - -V r,
+
12
a folluw
be hamal
page
it
vq (o.00031825
G°79.68
-38 62)
- Vg(0.32495)
79-68
%3D
- 30 77Kn

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