An α-particle has a charge of +2e and a mass of 6.64 × 10⁻²⁷ kg. It is accelerated from rest through a potential difference of 1.89 × 10⁵ V and then enters a uniform magnetic field whose magnitude is 1.84 T. The α-particle moves perpendicular to the magnetic field at all times. What is (a) the speed of the α-particle, (b) the magnitude of the magnetic force on it, and (c) the radius of its circular path?The accompanying diagram shows:- A parallel plate capacitor with a potential difference between plates, labeled as Vₐ and V_b.- The α-particle is exiting the capacitor and entering a region with a uniform magnetic field (denoted as B pointing into the screen).- The path of the α-particle is depicted as a curved trajectory, moving in a circular arc.Questions to be answered:(a) Calculate the speed of the α-particle.(b) Determine the magnitude of the magnetic force acting on the α-particle.(c) Find the radius of the circular path the α-particle takes.Spaces are provided for the numerical answers with appropriate units:(a) [Number] [Units](b) [Number] [Units](c) [Number] [Units]

Answered: Image /qna-images/answer/a314ec05-92a1-488e-8bcb-8707df0d32e9.jpg

An a-particle has a charge of +2e and a mass of 6.64 x 10-27 kg. It is accelerated from rest through a potential difference that has a value of 1.89 x 10° V and then enters a uniform magnetic field whose magnitude is 1.84 T. The a-particle moves perpendicular to the magnetic field at all times. What is (a) the speed of the a-particle, (b) the magnitude of the magnetic force on it, and (c) the radius of its circular path? (a) Number (b) Number Parallel plate capacitor Units Units B (into screen)

An a-particle has a charge of +2e and a mass of 6.64 x 10-27 kg. It is accelerated from rest through a potential difference that has a value of 1.89 x 10° V and then enters a uniform magnetic field whose magnitude is 1.84 T. The a-particle moves perpendicular to the magnetic field at all times. What is (a) the speed of the a-particle, (b) the magnitude of the magnetic force on it, and (c) the radius of its circular path? (a) Number (b) Number Parallel plate capacitor Units Units B (into screen)

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

See similar textbooks

Related questions

Q: A proton moves with a speed of 8.0 x 10^6 m/s along the +x-axis. It enters a region where there is a…

Q: An ion with a charge of 1.6 x 10^-19 C moves at speed 1.0 x 10^6 m/s into and perpendicular to the…

Q: A proton moves perpendicularly to a uniform magnetic field at 3.0 ✕ 107 m/s and exhibits an…

A: The magnetic force acting on a charged particle in motion can be given by F=qv×B The force acting on…

Q: An a-particle has a charge of +2e and a mass of 6.64 x 10-27 kg. It is accelerated from rest through…

A: Lorentz Force on an charged particle moving in an uniform magnetic field: When a charged particle is…

Q: proton is moving in the −z direction. The speed of the proton is 5.2×103 m/s. The proton enters a…

A: Velocity of proton is v=5.2×103 m/s in -z direction. Magnetic field is B=0.21 T pointing in -y…

Q: Given y-z plane. An electron having velocity v= −2.2×10^8 j m/s enters a uniform magnetic field of…

A: The expression for the required magnetic force is,

Q: Öne component of a magnetic field has a magnitude of 0.0261 T and points along the +x axis, while…

Q: An electron moving with a speed of 5.62 x 106 m/s in the positive y direction experiences zero…

Q: An electron moves with a speed of 9 x 106 m/s along the +x-axis. It enters a region where there is a…

A: Speed of electron is v=9×106 m/s along +x-axis. Magnetic field is B=3 T directed at an angle 55° to…

Q: A proton moves perpendicularly to a uniform magnetic field at 3.0 ✕ 107 m/s and exhibits an…

A: The expression for find magnitude of magnetic field is F=qvBma=qvBB=maqv

Q: A proton moving at 5.80 × 10 m/s through a magnetic field of magnitude 1.78 T experiences a magnetic…

A: Given in qustion - Speed of proton(v) = Magnitude of magnetic field(B) = Magnitude of the force(F) =…

Q: A proton moves through a magnetic field of magnitude 1.40 T with speed 5.00 x 10° m/s. What is the…

A: Magnetic force F = qvB

Q: proton moves with a velocity of = (5î − 5ĵ + k) m/s in a region in which the magnetic field is =…

A: Given: Velocity of proton is v→=5i^-5j^+k^ m/s Magnetic field is B→=i^+2j^-k^ T Note: Charge on…

Q: An electron travels at a speed of 2.0x10^4 m/s through a uniform magnetic field whose magnitude is…

A: Given: The speed of the electron is v=2X104 m/s. The magnitude of magnetic filed is B=1.2X10-3 T.…

Q: electron is accelerated through 2.05 x 103 V from rest and then enters a uniform 2.90-T magnetic…

Q: The electrons in the beam of a television tube have a kinetic energy of 3.53 X 10^-15 J. Initially,…

A: The kinetic energy is given by, KE=12mv2 The mass of electron is m=9.1×10-31 kg. Substitute the…

Q: An a-particle has a charge of +2e and a mass of 6.64 × 10-27 kg. It is accelerated from rest through…

Q: An electron (charge −1.60×10−19C) moves at 2.20×105m/s through a uniform 1.55 T magnetic field that…

Q: Determine the components of the total force on the proton. A proton moves through a region of space…

A: particle = proton magnetic field = 0.49i^ + 0.40j^ T Electric field = 2800i^ - 4500j^ Vmvelocity =…

Q: In the figure , a negative charged particle of mass 5.01 × 10-27 kg and charge 3.20 × 10-19 C moves…

A: Here , mass ,m= 5.01×10-27 kg Charge ,q= 3.2×10-19C Magnetic field ,B= 0.123 T Magnetic force…

Q: An electron in a Cathode-Ray Television Tube moves toward the front of the tube with a speed of 8.0…

A: Given Speed of electron v=8×106 m/s Magnetic field B=0.025T angle θ=60

Q: The magnetic field of the earth at a certain place is directed vertically downward and has a…

A: The magnetic force on a charged particle moving in the magnetic field is where, q is the charge, v…

Q: An electron with a speed of 1.2 x 102 m/s enters a magnetic field of 0.0020 T at 90 degrees to the…

A: The objective of the question is to determine the instantaneous acceleration of an electron as it…

Q: A particle with charge 1.70 C moves through a uniform magnetic field. At one instant the velocity of…

Q: An electron moves across Earth’s equator at a speed of 2.5 x 106 m/s and a direction 35o north of…

A: Given that, Earth's magnetic field B=0.1×10-4 TCharge of electron q=1.6×10-19 CSpeed of electron…

Q: Aircraft sometimes acquire small static charges. Suppose a supersonic jet has a 0.65 μC charge and…

Q: The solar wind is a thin, hot gas given off by the sun. Charged particles in this gas enter the…

Q: A proton travels with a speed of 5.10 ✕ 106 m/s at an angle of 57° with the direction of a magnetic…

A: (a) Given data : Speed of the proton, v = 5×106 m/s Magnetic field, B…

Q: A proton moving at 4.30 x 106 m/s through a magnetic field of magnitude 1.78 T experiences a…

Q: A proton moves with a velocity of = (5î − 5ĵ + ) m/s in a region in which the magnetic field is =…

A: Given value--- velocity = (5î − 5ĵ + ) m/s magnetic field = (î + 2ĵ ) T. We have to find---…

Q: An alpha particle travels at a velocity of magnitude 670 m/s through a uniform magnetic field of…

A: given An alpha particle travels at a velocity of magnitude 670 m/s through a uniform magnetic…

Concept explainers

Magnetic Force

A magnetic force arises when a charged particle or a current-carrying conductor is placed in a magnetic field. It is created because of the movement of the charged particles.

Question

100%

An α-particle has a charge of +2e and a mass of 6.64 × 10⁻²⁷ kg. It is accelerated from rest through a potential difference of 1.89 × 10⁵ V and then enters a uniform magnetic field whose magnitude is 1.84 T. The α-particle moves perpendicular to the magnetic field at all times. What is (a) the speed of the α-particle, (b) the magnitude of the magnetic force on it, and (c) the radius of its circular path?

The accompanying diagram shows:
- A parallel plate capacitor with a potential difference between plates, labeled as Vₐ and V_b.
- The α-particle is exiting the capacitor and entering a region with a uniform magnetic field (denoted as B pointing into the screen).
- The path of the α-particle is depicted as a curved trajectory, moving in a circular arc.

Questions to be answered:
(a) Calculate the speed of the α-particle.
(b) Determine the magnitude of the magnetic force acting on the α-particle.
(c) Find the radius of the circular path the α-particle takes.

Spaces are provided for the numerical answers with appropriate units:
(a) [Number] [Units]
(b) [Number] [Units]
(c) [Number] [Units]

Expert Solution

This question has been solved!

Explore an expertly crafted, step-by-step solution for a thorough understanding of key concepts.

This is a popular solution!

SEE SOLUTION Check out a sample Q&A here

Step 1

VIEW

Step 2

VIEW

Trending now

This is a popular solution!

Step by step

Solved in 2 steps with 2 images

SEE SOLUTION Check out a sample Q&A here

Knowledge Booster

Learn more about

Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, physics and related others by exploring similar questions and additional content below.

Similar questions

An a-particle has a charge of +2e and a mass of 6.64 x 10-27 kg. It is accelerated from rest through a potential difference that has a value of 1.46 x 106 V and then enters a uniform magnetic field whose magnitude is 1.99 T. The a-particle moves perpendicular to the magnetic field at all times. What is (a) the speed of the a-particle, (b) the magnitude of the magnetic force on it, and (c) the radius of its circular path? (a) Number i (b) Number i (c) Number Parallel plate capacitor VA VB Units Units Units VB x r V x x x B (into screen)
A proton moves perpendicularly to a uniform magnetic field at 3.0 ✕ 107 m/s and exhibits an acceleration of 1.0 ✕ 1013 m/s2 in the +x-direction when its velocity is in the +z-direction. Determine the magnitude and direction of the field.
A proton is accelerated in a particle accelerator from rest through a potential difference of 0.130 kV. If the proton then passes through a uniform magnetic field of magnitude 0.120 T that is perpendicular to the proton's path, what is the radius of the path that the proton will take through the magnetic field? Give your answer in cm. (The mass of a proton is 1.672*10^-27 kg.)
A positively charged particle of mass 8.84 x 10-8 kg is traveling due east with a speed of 79.2 m/s and enters a 0.346-T uniform magnetic field. The particle moves through one-quarter of a circle in a time of 3.34 x 10-3 s, at which time it leaves the field heading due south. All during the motion the particle moves perpendicular to the magnetic field. (a) What is the magnitude of the magnetic force acting on the particle? (b) Determine the magnitude of its charge. (a) Number i (b) Number i Units Units B (out of screen)
A positively charged particle of mass 6.82 x 10-8 kg is traveling due east with a speed of 64.2 m/s and enters a 0.397-T uniform magnetic field. The particle moves through one-quarter of a circle in a time of 4.06 × 10-³ s, at which time it leaves the field heading due south. All during the motion the particle moves perpendicular to the magnetic field. (a) What is the magnitude of the magnetic force acting on the particle? (b) Determine the magnitude of its charge. (a) Number (b) Number pi i Units Units V < B (out of screen)
A uniform magnetic field B = 1.7 x 10-4 T exists in +x direction. A proton (q = +e, and mp = 1.67 x 10-27 kg) is shot through the field in the +y direction with a speed of 3.5 x 105 m/s. Find the magnitude and direction of the magnetic force FB on the proton.
A proton (with mass mp = 1.67 x 10-27 kg, charge qp = 1.6 x 10-19 C) moving with a speed of 0.80 x 105 m/s, enters the Earth’s magnetic field (B= 55.0 μμT, Northbound). If the proton is shot eastward, the magnetic force acting on it should be Group of answer choices 8.08 x 10-16 N downward 7.04 x 10-19 N West-bound 7.04 x 10-19 N upward 7.04 x 10-19 N downward
A charged particle moves with a speed of 6.0×103 m/s perpendicularly into an uniform magnetic field of magnitude 0.20 T. The charge of the particle is 5.8 ×10-16 C, mass of the particle is 1.2 ×10-21kg. (a) What is the magnitude of the magnetic force on the particle? (b) What could be the radius of the path of the particle if it moves inside the B-field?(c) To avoid the particle being deflected by the magnetic field, (so particle can move straight through the B-field,) an electric field is applied at the same location. What is the magnitude of the E-field? HTML EditorKeyboard Shortcuts