An 8.00-L reaction vessel at 491C contained 0.65 mol H2, 0.275 mol I2, and 3.000 mol HI. Assuming that the substances are at equilibrium, find the value of Kc at 491°C for the reaction of hydrogen and iodine to give hydrogen iodide. The equation is  H2(g) + I2(g) ↔ 2HI(g) Express your answer to two decimal places.

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