Solve all parts for upvote ### Physics Problem: Analyzing Forces on an Inclined Plane**Problem Statement:**An object, specifically a crate with a weight of 1520 N, is positioned on an incline that rises at an angle of 30.0 degrees from the horizontal. The crate is connected via a massless rope, which extends at an angle of 22.0 degrees above the ramp's surface. The static friction coefficient (\( \mu_s \)) between the crate and the ramp is 0.650, and it is assumed that the pulley involved in the setup has neither significant mass nor friction.**Tasks:**1. Draw a free-body diagram illustrating all forces acting on the masses.2. Determine the maximum weight (\( w \)) that can keep the crate stationary on the ramp.**Diagram Explanation:**The diagram shows a crate on an inclined plane (ramp) which is at a 30.0-degree angle with respect to the horizontal. A rope is attached to the crate and goes over a pulley, pulling a separate hanging weight labeled \( w = ? \). The rope makes a 22.0-degree angle with the surface of the incline, not aligned with the direct incline angle. In the free-body diagram, the forces that need to be accounted for include:- The gravitational force acting on the crate (1520 N, directed downwards).- Frictional force opposing the motion (static friction).- Tension in the rope acting in the direction that opposes slipping down the ramp.- Normal force acting perpendicular to the surface of the incline.By analyzing these forces, one can determine the conditions for equilibrium and solve for the maximum allowable weight \( w \) that maintains the crate in a stationary position on the ramp.

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An 1520-N crate is to be held in place on a ramp that nises at 30.0° above the horizontal. The massless rope attached to the crate makes a 22.0° angle above the surface of the ramp. The coefficients of friction between the crate and the surface of the ramp is µs = 0.650. The pulley has no appreciable mass or friction. Draw a free-body diagrum for masses Can What is the MAXImum weight w that this crate stationary on the 7 ramp L Crate 30.0⁰ 22.0 Tamp w = ? be used to hold

An 1520-N crate is to be held in place on a ramp that nises at 30.0° above the horizontal. The massless rope attached to the crate makes a 22.0° angle above the surface of the ramp. The coefficients of friction between the crate and the surface of the ramp is µs = 0.650. The pulley has no appreciable mass or friction. Draw a free-body diagrum for masses Can What is the MAXImum weight w that this crate stationary on the 7 ramp L Crate 30.0⁰ 22.0 Tamp w = ? be used to hold

Physics for Scientists and Engineers: Foundations and Connections

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ISBN:9781133939146

Author:Katz, Debora M.

Publisher:Katz, Debora M.

Chapter6: Applications Of Newton’s Laws Of Motion

Section: Chapter Questions

Problem 24PQ: Lisa measured the coefficient of static friction between two pairs of running shoes and the track in...

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Newton’s Third Law of Motion

The horse pulls the cart and the cart pulls the horse in response as per Newton third law. So the big question is, “Don’t the two forces cancel each other? How does the cart accelerate?”

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Solve all parts for upvote

### Physics Problem: Analyzing Forces on an Inclined Plane

**Problem Statement:**
An object, specifically a crate with a weight of 1520 N, is positioned on an incline that rises at an angle of 30.0 degrees from the horizontal. The crate is connected via a massless rope, which extends at an angle of 22.0 degrees above the ramp's surface. The static friction coefficient (\( \mu_s \)) between the crate and the ramp is 0.650, and it is assumed that the pulley involved in the setup has neither significant mass nor friction.

**Tasks:**
1. Draw a free-body diagram illustrating all forces acting on the masses.
2. Determine the maximum weight (\( w \)) that can keep the crate stationary on the ramp.

**Diagram Explanation:**
The diagram shows a crate on an inclined plane (ramp) which is at a 30.0-degree angle with respect to the horizontal. A rope is attached to the crate and goes over a pulley, pulling a separate hanging weight labeled \( w = ? \). The rope makes a 22.0-degree angle with the surface of the incline, not aligned with the direct incline angle.

In the free-body diagram, the forces that need to be accounted for include:
- The gravitational force acting on the crate (1520 N, directed downwards).
- Frictional force opposing the motion (static friction).
- Tension in the rope acting in the direction that opposes slipping down the ramp.
- Normal force acting perpendicular to the surface of the incline.

By analyzing these forces, one can determine the conditions for equilibrium and solve for the maximum allowable weight \( w \) that maintains the crate in a stationary position on the ramp.

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