Amplifier’s Frequency Response Vec = 20V Vcc R1 = 40 kohm R2 = 10 kohm Rc =4 kohm RE-2 kohm Rs-1 kohm RL = 2.2 kohm Cs = 10 uF Rc Cc =1 uF CE = 20 uF Cbc = 4 pF Cbe = 36 pF Cce =1 pF R1 Cc Cwi = 6 pF Cwo -8 pF C; Beta = 100 Cce + Cwo RL R2 Cw Cbe Calculate Rin(base). 1.576 ko а. b. 1.679 ka 1.812 ko c. d. 1.987 kQ
Amplifier’s Frequency Response Vec = 20V Vcc R1 = 40 kohm R2 = 10 kohm Rc =4 kohm RE-2 kohm Rs-1 kohm RL = 2.2 kohm Cs = 10 uF Rc Cc =1 uF CE = 20 uF Cbc = 4 pF Cbe = 36 pF Cce =1 pF R1 Cc Cwi = 6 pF Cwo -8 pF C; Beta = 100 Cce + Cwo RL R2 Cw Cbe Calculate Rin(base). 1.576 ko а. b. 1.679 ka 1.812 ko c. d. 1.987 kQ
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
Section: Chapter Questions
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Transcribed Image Text:Amplifier's Frequency Response
Vcc
Vcc = 20V
R1 = 40 kohm
R2 = 10 kohm
Rc =4 kohm
RE=2 kohm
Rs = 1 kohm
RL = 2.2 kohm
Rc
Cs = 10 uF
Cc =1 uF
CE = 20 uF
Cbc = 4 pF
Cbe = 36 pF
Cce-1 pF
Cwi =6 pF
Cwo =8 pF
Beta = 100
Cc
Cce
R1
Rs
R2
Cbe
Rg
Calculate Rin(base).
1.576 kQ
а.
b. 1.679 kO
1.812 kQ
c.
d.
1.987 kQ
+
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