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ample 1.3.1 Check lim inf[0, n/(n + 1)) = lim sup[0, n/(n + 1)) = [0, 1). We can now give an interpretation of lim inf,-0 An and lim sup,, 848

ample 1.3.1 Check lim inf[0, n/(n + 1)) = lim sup[0, n/(n + 1)) = [0, 1). We can now give an interpretation of lim inf,-0 An and lim sup,, 848

Advanced Engineering Mathematics
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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To make sure you understand the definitions, you should check the fol ample as an exercise. ample 1.3.1 Check lim inf[0, n/(n +1)) = lim sup[0, n/(n + 1)) = [0, 1). %3D We can now give an interpretation of lim infno An and lim sup,. A mma 1.3.1 Let {A,} be a sequence of subsets of S2. a) For lim sup we have the interpretation
Transcribed Image Text:To make sure you understand the definitions, you should check the fol ample as an exercise. ample 1.3.1 Check lim inf[0, n/(n +1)) = lim sup[0, n/(n + 1)) = [0, 1). %3D We can now give an interpretation of lim infno An and lim sup,. A mma 1.3.1 Let {A,} be a sequence of subsets of S2. a) For lim sup we have the interpretation
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