AMPAD™A67° 17'BCDTHE FOUR SIDED CLOSED TRAVERSEHAS THE FOLLOWING ANGLES &DISTAN CESA= 51° 23'B = 105°39'C=78° 11'D= 124°47'AB = 713.93FT,ABBC= 606.06FTCD = 391.27 FT.DA = 781.18 FT.THE AZIMUTH OF AB IS67°17'ASSIGNING AN ORIGIN TO POINTA(N300, E100) AND USING THELIN-ADJUSTED LATITUDES & DEPARTURESFROM TRAVERSE HOMEWORKASSIGNMENTI.J. COMPUTE THE COORDINATES FORPOINTS B, C & D (30 POINTS).

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Answered: AMPAD™ A 67° 17' B C D THE FOUR SIDED…

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

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PROBLEM 1 Given the following interior angles (angles-to-the-right) of a five-sided closedpolygon traverse and if the azimuth of side AB is fixed at 74°31'17", determine the adjusted azimuth of line EA.A =105°13'14"; B = 92°36'06"; C = 67°15'22"; D = 217°24'30"; E = 57°30"38". (Note: line BC bears NW.) NEEDED ANS: Compute the relative precision for the traverse of Problem 1 if the lengths of the sides (in feet) are as follows: AB = 2157.34; BC =1722.58;CD =1318.15; DE =1536.06; and EA =1785.58. (Note: Assume units of feet for all distances.) Round off the denominator to two decimal places.
5) [Book problem 7.17] Course AB of a five-sided traverse runs due north. From the given balanced interior angles to the right (A - E as shown below), compute and tabulate the bearings and azimuths from north for each side of the traverse. A = 156°23'53", B = 53°36'08", C = 83°15'58", D = 153°52'00", and E = 92°52'01" (Hints: you are asked to compute the azimuths and bearings of a 5-sided polygon traverse, whose first course, AB, runs due north, and whose balanced interior angles to the right are given. Use the tabular method demonstrated in class.)
PROBLEM 1 Given the following interior angles (angles-to-the-right) of a five-sided closedpolygon traverse and if the azimuth of side AB is fixed at 74°31'17", determine the adjusted azimuth of line EA.A =105°13'14"; B = 92°36'06"; C = 67°15'22"; D = 217°24'30"; E = 57°30"38". (Note: line BC bears NW.) PROBLEM 2 Compute the linear misclosure for the traverse of Problem 1 if the lengths of the sides (in feet) are as follows: AB = 2157.34; BC =1722.58;CD =1318.15; DE =1536.06; and EA =1785.58. (Note: Assume units of feet for all distances.) NEEDED ANS: Using the compass (Bowditch) rule, adjust the departures and latitudes of the traverse in Problem 1 considering the length of Problem 2. If the coordinates of station A are X = 20,000 ft and Y = 15,000 ft, calculate the final adjusted angles at stations C.(The answer must be in the form of degree, minutes, seconds. Round off the answer to whole number.)
27. Given a closed traverse with two interior angles as shown below, and the azimuth of line AB as 350. If the coordinates of point A are XA-1000 and YA= 1000, and the distance AB is 455.80 ft., the X coordinate at B is ft. 105 47 a) 1079.15 b) 920,85 c) 1448.88 d) None of the above
6.16 See Figure 6.24. The five-sided, closed traverse has the following angles and for 15 distances: B umise los A = 38°30' B = 100°38' C = 149°50 Basigns no 11100D = 85°59' AB= 371.006 m BC = 110.222 m CD = 139.872 m DE 103.119 m E = 165°03' EA = 319.860 m +2- 725121 Moto C D unde Side AB has an azimuth of 306°31'. (a) Perform a check for angular closure. (b) Compute both bearings and azimuths for all sides. (c) Compute the latitudes and departures. 201 Az. = 306°31' E FIGURE 6.24 Sketch for Problem 6.16. A

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