AMPAD™A67° 17'BCDTHE FOUR SIDED CLOSED TRAVERSEHAS THE FOLLOWING ANGLES &DISTAN CESA= 51° 23'B = 105°39'C=78° 11'D= 124°47'AB = 713.93FT,ABBC= 606.06FTCD = 391.27 FT.DA = 781.18 FT.THE AZIMUTH OF AB IS67°17'ASSIGNING AN ORIGIN TO POINTA(N300, E100) AND USING THELIN-ADJUSTED LATITUDES & DEPARTURESFROM TRAVERSE HOMEWORKASSIGNMENTI.J. COMPUTE THE COORDINATES FORPOINTS B, C & D (30 POINTS).

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Answered: AMPAD™ A 67° 17' B C D THE FOUR SIDED…

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

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PROBLEM 1 Given the following interior angles (angles-to-the-right) of a five-sided closedpolygon traverse and if the azimuth of side AB is fixed at 74°31'17", determine the adjusted azimuth of line EA.A =105°13'14"; B = 92°36'06"; C = 67°15'22"; D = 217°24'30"; E = 57°30"38". (Note: line BC bears NW.) NEEDED ANS: Compute the relative precision for the traverse of Problem 1 if the lengths of the sides (in feet) are as follows: AB = 2157.34; BC =1722.58;CD =1318.15; DE =1536.06; and EA =1785.58. (Note: Assume units of feet for all distances.) Round off the denominator to two decimal places.
5) [Book problem 7.17] Course AB of a five-sided traverse runs due north. From the given balanced interior angles to the right (A - E as shown below), compute and tabulate the bearings and azimuths from north for each side of the traverse. A = 156°23'53", B = 53°36'08", C = 83°15'58", D = 153°52'00", and E = 92°52'01" (Hints: you are asked to compute the azimuths and bearings of a 5-sided polygon traverse, whose first course, AB, runs due north, and whose balanced interior angles to the right are given. Use the tabular method demonstrated in class.)
A closed traverse has the following data: Course Length Azimuth Interior Angle to the Right AB 141.657 163°48'53" | A = 95°02'30" B = 138°54'49" C = 69°41'08" D = 147°47'42" BC |137.544 CD 152.132 DE 128.562 EA 155.436 E = 88°33'51" a.) Adjust the traverse using transit rule. b.) Compute the area (m²) of the traverse.
Refer to the closed traverse in the following figure. 1.) The interior angle B, which is unknown. 2.) Determine the azimuth from South of lines AB and DE. 3.) Identify the closed traverse's area.
PROBLEM 1 Given the following interior angles (angles-to-the-right) of a five-sided closedpolygon traverse and if the azimuth of side AB is fixed at 74°31'17", determine the adjusted azimuth of line EA.A =105°13'14"; B = 92°36'06"; C = 67°15'22"; D = 217°24'30"; E = 57°30"38". (Note: line BC bears NW.) PROBLEM 2 Compute the linear misclosure for the traverse of Problem 1 if the lengths of the sides (in feet) are as follows: AB = 2157.34; BC =1722.58;CD =1318.15; DE =1536.06; and EA =1785.58. (Note: Assume units of feet for all distances.) NEEDED ANS: Using the compass (Bowditch) rule, adjust the departures and latitudes of the traverse in Problem 1 considering the length of Problem 2. If the coordinates of station A are X = 20,000 ft and Y = 15,000 ft, calculate the final adjusted angles at stations C.(The answer must be in the form of degree, minutes, seconds. Round off the answer to whole number.)
Balance the following interior angles (angles-to-the-right) of a six-sided closed polygon traverse. If the bearing of side AB is fixed at N68°04'21"E, calculate the azimuths of the remaining sides. A = 138°6'17"; B = 87°19'51"; C = 71°27'06"; D = 223°56'11"; E = 108°5'46'; F = 191°4'37". (Note: Line BC bears NW.)
The tabulation shown below is the traverse data of a five-sided closed polygon. If the azimuth from the north of side AB is fixed at 74° 31’ 17”, determine the following: (Note: Line BC bears NW.) 1.1 The balanced interior angle A is 105° 13’ 1.2 The balanced interior angle B is 92° 36’ 1.3 The balanced interior angle C is 67° 15’ 1.4 The balanced interior angle D is 217° 24’ 1.5 The balanced interior angle E is 57° 30’
S62°30'E is incorrect. The answer should be N 62°30' W. Sketch the close traverse.
2. Given the following sketch and tabulated data for a closed traverse in which the length of DE and the bearing of EF have not been observed in the field. Find the length and bearing of closing line DF, length of DE and bearing of EF. COURSE LENGTH (m) BEARING AB 492.88 N 05°30' E N 46°03' E S67°24' E ВС 845.85 CD 852.18 S 12°17' E DE EF 1210.50 FA 661.26 N 55°27' W
A survey is performed on a closed traverse as shown in the figure below. The course of the traverse is alphabetical (A-B-C-D-E-F-A). For the closed traverse, determine the following: a. The unknown angle at point F. b. Assume line AB has a bearing of "True East". The bearings and azimuths of all other courses (lines) of the traverse. A 127°37'10" B E 70°33'20" 38*16'45" 119°3'25 C 99°36′56*
27. Given a closed traverse with two interior angles as shown below, and the azimuth of line AB as 350. If the coordinates of point A are XA-1000 and YA= 1000, and the distance AB is 455.80 ft., the X coordinate at B is ft. 105 47 a) 1079.15 b) 920,85 c) 1448.88 d) None of the above
6.16 See Figure 6.24. The five-sided, closed traverse has the following angles and for 15 distances: B umise los A = 38°30' B = 100°38' C = 149°50 Basigns no 11100D = 85°59' AB= 371.006 m BC = 110.222 m CD = 139.872 m DE 103.119 m E = 165°03' EA = 319.860 m +2- 725121 Moto C D unde Side AB has an azimuth of 306°31'. (a) Perform a check for angular closure. (b) Compute both bearings and azimuths for all sides. (c) Compute the latitudes and departures. 201 Az. = 306°31' E FIGURE 6.24 Sketch for Problem 6.16. A

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