AMPAD A 67°17 ل P THE FOUR SIDED CLOSED TRAVERSE HAS THE FOLLOWING ANGLES & DISTANCES. A 51°23' B 105°39' C 78° 11' AB=713.93 FT. BC= 606.06 FT. CD = 391.27 FT. D 124°47 DA = 781.18 FT THE AZIMUTH OF AB 15 67° 17'. UTILIZING THE INFORMATION FROM THE TRAVERSE HOMEWORK ASSIGNMENT I 1. COMPUTE THE LATITUDES & DEPARTURES (24POINTS) 2.COMPUTE THE LINEAR MIS-CLOSURE (GPOINTS *DO NOT ADJUST THE LATITUDES & DEPARTURES AFTER COMPUTING THE LINEAR MIS-CLOSLIRE