Among 200 randomly selected Internet users, it was found that 89 of them use the Internet for making travel plans. Use asignificance level of alpha equal to 0.01 to test the claim that at least 50% of Internet users use it for making travel plans.What is the test statistic?O A. -1.56О в. 1.56OC.-1.57O D. 1.57QUESTION 11Among 200 randomly selected Internet users, it was found that 89 of them use the Internet for making travel plans. Use asignificance level of alpha equal to 0.01 to test the claim that at least 50% of Internet users use it for making travel plans.What is thep-value for this test?OA. 0.0594OB. 0.0582OC. 0.9406OD.0.1188Clhck Save and Submit to save and submit. Click Save All Answers to save ad ansuers.Save All Answers44 FType here to search1510/05/17PriScInsertDeleteF10F11F12F6F7F8F9F5EscF1F2F3F4Backs&%2357080* COCO

Solution: Given information: n= 200 Sample size of internet users. x = 89 internet users use the…

Answered: Among 200 randomly selected Internet…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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Below indicate whether the appropriate test would be an independent t-test, dependent t-test, One-way ANOVA, or z-test. A researcher wants to know if people find baby animals cuter than adult animals. All of the participants in a study are shown 10 pictures of baby animals and 10 pictures of adult animals. They are asked to rate (on a 1 to 10 scale) how cute they think each animal is.
A dietitian wishes to see if a person's cholesterol level will change if the diet is supplemented by a certain mineral. Seven subjects were pretested and then took the mineral supplement for a six-week period. The results are shown below in the table. Use a paired samples t-chart at a = 0.01 significance level to see difference (Before - After) between the cholesterol levels. State the hypotheses and conclusion. Also, conduct a 99% confidence interval. Subject 1 Before 210 After 190 2 205 170 3 208 210 4 192 188 5 178 173 6 244 228 7 211 198
The coach of a very popular men’s basketball team claims that the average distance the fans travel to the campus to watch a game is 35 miles. The team members feel otherwise. A sample of 16 fans who travel to games was randomly selected and yielded a mean of M= 36 miles and s= 5 miles. Test the coach’s claim at the 5% (.05) level of significance. one-tailed or two-tailed test: State the hypotheses: df= tα or t value for the critical region = sM = t (test statistic)= Decision:
Previously, an organization reported that teenagers spend 12.5 hours per week, on average, on the phone. The organization thinks that, currently, the mean is lower. Twenty-three randomly chosen teenagers were asked how many hours per week they spend on the phone, with the following results (in hours): 10.4, 10.4, 17.3, 11.2, 10, 15.2, 9.5, 5.8, 12.5, 11.8, 7.3, 10.6, 11.5, 16.2, 16.5, 14.3, 12.3, 9.9, 13.7, 8.6, 11.3, 13, 16.5 Perform a hypothesis test using a 10% level of significance. Step 1: State the null and alternative hypotheses. Ho: pv 12.5 12.5 (So we will be performing a left-tailed Vv test.) Step 2: Assuming the null hypothesis is true, determine the features of the distribution of point estimates using the Central Limit Theorem. By the Central Limit Theorem, we know that the point estimates are t-distributed with distribution mean and distribution standard deviation Step 3: Find the p-value of the point estimate. = P(tv sv p-value = Step 4: Make a Conclusion About the nulI…
In a sample of 367 students, 132 said that they enjoy science. Using a significance level of a = 0.03, determine the test statistic and p-value when testing the claim that less than 35% of students enjoy science. Round the test statistic to two decimal places and the p-value to four decimal places. The test statistic is The p-value is
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give an example of a study for which the independent sample t-test is appropiate
A Michigan study concerning preference for outdoor activities used a questionnaire with a six-point Likert-type response in which 1 designated "not important" and 6 designated "extremely important." A random sample of n1 = 41 adults were asked about fishing as an outdoor activity. The mean response was x1 = 4.9. Another random sample of n2 = 50 adults were asked about camping as an outdoor activity. For this group, the mean response was x2 = 5.7. From previous studies, it is known that ?1 = 1.6 and ?2 = 1.5. Does this indicate a difference (either way) regarding preference for camping versus preference for fishing as an outdoor activity? Use a 5% level of significance.Note: A Likert scale usually has to do with approval of or agreement with a statement in a questionnaire. For example, respondents are asked to indicate whether they "strongly agree," "agree," "disagree," or "strongly disagree" with the statement. (a) What is the level of significance? .05 State the null and alternate…
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A company claims that less than 30% of people who both work and live in Newcastle. A study revealed that among a random sample of 200 people working in Newcastle, 62 also lived in Newcastle. Does the sample support the company’s claim? Use a level of significance of 0.01.
Only need the last question. Please put anwsers in bold thank you! A researcher with the Department of Education followed a cohort of students who graduated from high school in a certain year, monitoring the progress the students made toward completing a bachelor's degree. One aspect of his research was to determine whether students who first attended community college took longer to attain abachelor's degree than those who immediately attended and remained at a 4-year institution.

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