Ammonia reacts with oxygen to form nitrogen dioxide and water according to the following equation: 4NH3(gas) + 7O2(g) ---> 4NO2(g) + 6H2O(g) You react ammonia and oxygen, and at the end of the experiment you find that you produced 23 g of water and have 8.52 g of ammonia left over. Determine the mass of oxygen reacted. Group of answer choices 71.49 g O2 17.66 g O2 40.85 g O2 35.02 g O2 47.66 g O2
Ammonia reacts with oxygen to form nitrogen dioxide and water according to the following equation: 4NH3(gas) + 7O2(g) ---> 4NO2(g) + 6H2O(g) You react ammonia and oxygen, and at the end of the experiment you find that you produced 23 g of water and have 8.52 g of ammonia left over. Determine the mass of oxygen reacted. Group of answer choices 71.49 g O2 17.66 g O2 40.85 g O2 35.02 g O2 47.66 g O2
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Ammonia reacts with oxygen to form nitrogen dioxide and water according to the following equation:
4NH3(gas) + 7O2(g) ---> 4NO2(g) + 6H2O(g)
You react ammonia and oxygen, and at the end of the experiment you find that you produced 23 g of water and have 8.52 g of ammonia left over. Determine the mass of oxygen reacted.
Group of answer choices
71.49 g O2
17.66 g O2
40.85 g O2
35.02 g O2
47.66 g O2
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