Ammonia reacts with oxygen according to the equation 4 NH3(g) + 5O₂(g) → 4 NO(g) + 6 H₂O(g). If the rate ammonia consumption is 3.8 x10-5 M/s, what is the rate of appearance of H₂O(g)? I

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**Ammonia Reaction with Oxygen**

Ammonia reacts with oxygen according to the equation:

\[ 4 \, \text{NH}_3(g) + 5 \, \text{O}_2(g) \rightarrow 4 \, \text{NO}(g) + 6 \, \text{H}_2\text{O}(g) \]

If the rate of ammonia consumption is \( 3.8 \times 10^{-5} \, \text{M/s} \), what is the rate of appearance of \(\text{H}_2\text{O}(g)\)?
Transcribed Image Text:**Ammonia Reaction with Oxygen** Ammonia reacts with oxygen according to the equation: \[ 4 \, \text{NH}_3(g) + 5 \, \text{O}_2(g) \rightarrow 4 \, \text{NO}(g) + 6 \, \text{H}_2\text{O}(g) \] If the rate of ammonia consumption is \( 3.8 \times 10^{-5} \, \text{M/s} \), what is the rate of appearance of \(\text{H}_2\text{O}(g)\)?
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The rate of the formation of the product or the rate of disappearance of the reactants is known as the rate of reaction. The rate of reaction depends on several factors, such as the concentration of reactants, temperature, pressure, and the nature of the reactants. Note: The concentration of the reactants decreases with time, hence we use the negative sign in the case of the reactants.

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