aminated wood beam consists of eight 2.25 in. × 5.25-in. planks glued together to form a section b = 5.25 in. wide by d = 18 in. deep, as shown. If the allowable strength of the glue in shear is 110 psi, determine (a) the maximum uniformly distributed load w that can be applied over the full length of the beam if the beam is simply supported and has a span of L = 18 ft. (b) the shear stress in the glue joint at H, which is located 4.5 in. above the bottom of the beam and at a distance of x = 51 in. from the left support. Assume that the beam is subjected to the load w determined in part (a). (c) the maximum tension bending stress in the beam when the load of part (a) is applied. Determine the maximum allowable shear force in the beam. Answer: Vmax = lb
A laminated wood beam consists of eight 2.25 in. × 5.25-in. planks glued together to form a section b = 5.25 in. wide by d = 18 in. deep, as shown. If the allowable strength of the glue in shear is 110 psi, determine
(a) the maximum uniformly distributed load w that can be applied over the full length of the beam if the beam is simply supported and has a span of L = 18 ft.
(b) the shear stress in the glue joint at H, which is located 4.5 in. above the bottom of the beam and at a distance of x = 51 in. from the left support. Assume that the beam is subjected to the load w determined in part (a).
(c) the maximum tension bending stress in the beam when the load of part (a) is applied.
Answer: Vmax = lb
Answer: wmax = lb/ft
Answer: V = lb
Answer: QH = in.3
Answer: τH= psi
Answer: Mmax = lb-ft
Answer: σx= psi
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