Amelia is decorating the outside of a box in the shape of a square pyramid. The figure below shows a net for the box. 5 m 3.7 m What is the surface area of the box, in square meters, that Amelia decorates?

Elementary Geometry For College Students, 7e
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ISBN:9781337614085
Author:Alexander, Daniel C.; Koeberlein, Geralyn M.
Publisher:Alexander, Daniel C.; Koeberlein, Geralyn M.
ChapterP: Preliminary Concepts
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**Problem: Calculating the Surface Area of a Square Pyramid**

Amelia is decorating the outside of a box in the shape of a square pyramid. The figure below shows a net for the box:

![Square Pyramid Net](https://example.com/figure)

### Description of the Net
The net consists of:
- One square base with each side measuring 3.7 meters.
- Four triangular faces, each with a base of 3.7 meters and a slant height of 5 meters.

### Illustration
The diagram shows the net of a square pyramid, which is composed of a central square with four triangles attached to each side. The triangles fold up to meet at a single point above the center of the square, forming the pyramid.

### Dimensions
- The side length of the square base: **3.7 meters**
- The slant height of the triangular faces: **5 meters**

### Problem Statement
What is the surface area of the box, in square meters, that Amelia decorates?

### Solution:

To find the surface area of a square pyramid, we need to calculate the area of the square base and the area of the four triangular faces.

**Step 1: Calculate the area of the square base.**

\[ \text{Area of the square} = \text{side}^2 \]
\[ \text{Area of the square} = 3.7 \times 3.7 \]
\[ \text{Area of the square} = 13.69 \text{ square meters} \]

**Step 2: Calculate the area of one triangular face.**

\[ \text{Area of one triangle} = \frac{1}{2} \times \text{base} \times \text{height} \]
\[ \text{Area of one triangle} = \frac{1}{2} \times 3.7 \times 5 \]
\[ \text{Area of one triangle} = 9.25 \text{ square meters} \]

**Step 3: Calculate the total area of the four triangular faces.**

\[ \text{Total area of triangles} = 4 \times \text{Area of one triangle} \]
\[ \text{Total area of triangles} = 4 \times 9.25 \]
\[ \text{Total area of triangles} = 37 \text{ square meters} \]

**Step 4: Calculate the total
Transcribed Image Text:**Problem: Calculating the Surface Area of a Square Pyramid** Amelia is decorating the outside of a box in the shape of a square pyramid. The figure below shows a net for the box: ![Square Pyramid Net](https://example.com/figure) ### Description of the Net The net consists of: - One square base with each side measuring 3.7 meters. - Four triangular faces, each with a base of 3.7 meters and a slant height of 5 meters. ### Illustration The diagram shows the net of a square pyramid, which is composed of a central square with four triangles attached to each side. The triangles fold up to meet at a single point above the center of the square, forming the pyramid. ### Dimensions - The side length of the square base: **3.7 meters** - The slant height of the triangular faces: **5 meters** ### Problem Statement What is the surface area of the box, in square meters, that Amelia decorates? ### Solution: To find the surface area of a square pyramid, we need to calculate the area of the square base and the area of the four triangular faces. **Step 1: Calculate the area of the square base.** \[ \text{Area of the square} = \text{side}^2 \] \[ \text{Area of the square} = 3.7 \times 3.7 \] \[ \text{Area of the square} = 13.69 \text{ square meters} \] **Step 2: Calculate the area of one triangular face.** \[ \text{Area of one triangle} = \frac{1}{2} \times \text{base} \times \text{height} \] \[ \text{Area of one triangle} = \frac{1}{2} \times 3.7 \times 5 \] \[ \text{Area of one triangle} = 9.25 \text{ square meters} \] **Step 3: Calculate the total area of the four triangular faces.** \[ \text{Total area of triangles} = 4 \times \text{Area of one triangle} \] \[ \text{Total area of triangles} = 4 \times 9.25 \] \[ \text{Total area of triangles} = 37 \text{ square meters} \] **Step 4: Calculate the total
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