am iSavedHelpSave & ExitA random variable is binomially distributed with n= 16 and T = .40. The expected value and standard deviation of the variables areMultiple Choice2.00 and 1.244.80 and 4006.40 and 1.962.00 and 1.2017 of 19Next >

Solution: Let X be the random variable. From the given information, the distribution is binomial…

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MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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H0 , test statistic, and p value please
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Systolic blood pressure readings are normally distributed with a mean of 121 and standard deviation of 15. If a person from the population was selected at random, find the probability that their blood pressure is in the acceptable range (between 114 and 140) for an athletic activity. A. Label and shade the normal distribution curve to model this problem.
Suppose that the distance of fly balls hit to the outfield (in baseball) is normally distributed with a mean of 236 feet and a standard deviation of 44 feet. We randomly sample 49 fly balls. Part (a) If X =average distance in feet for 49 fly balls, then give the distribution of X. Round your standard deviation to two decimal places. X ____, ________,_______ ~ . Part (b) What is the probability that the 49 balls traveled an average of less than 226 feet? (Round your answer to four decimal places.)Sketch the graph. Scale the horizontal axis for X. Shade the region corresponding to the probability. Part (c) Find the 70th percentile of the distribution of the average of 49 fly balls. (Round your answer to two decimal places.) ft †
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average number of pounds of meat that a person consumes per year is 218pounds. Assume that the standard deviation is 26 pounds and the distribution is approximately normal. 1- Find the probability that a person selected at random consumes less than 224 pounds per year 2-1f a sample of 50 individuals is selected find the probability that the mean of the sample will be less than 224 pounds per year
Americans receive an average of 20 Christmas cards each year. Suppose the number of Christmas cards is normally distributed with a standard deviation of 5. Let X be the number of Christmas cards received by a randomly selected American. Round all answers to 4 decimal places where possible.b. If an American is randomly chosen, find the probability that this American will receive no more than 23 Christmas cards this year. Incorrectc. If an American is randomly chosen, find the probability that this American will receive between 21 and 26 Christmas cards this year. d. 65% of all Americans receive at most how many Christmas cards? (Please enter a whole number)

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am i Saved Help Save & Exit A random variable is binomially distributed with n= 16 and T = .40. The expected value and standard deviation of the variables are Multiple Choice 2.00 and 1.24 4.80 and 400 6.40 and 1.96 2.00 and 1.20 17 of 19 Next >