Aluminum Eal = 10(10³) ksi AAB=0.09 in² 2.00 kip A 18 in.- Copper Ecu=18(10³) ksi ABC = 0.12 in² B 3.50 kip 3.50 kip -12 in. Figure 3 Steel Est = 29(10³) ksi ACD=0.06 in² 1.75 kip 1.75 kip 16 in. 1.50 kip D

Aluminum Eal = 10(10³) ksi AAB=0.09 in² 2.00 kip A 18 in.- Copper Ecu=18(10³) ksi ABC = 0.12 in² B 3.50 kip 3.50 kip -12 in. Figure 3 Steel Est = 29(10³) ksi ACD=0.06 in² 1.75 kip 1.75 kip 16 in. 1.50 kip D

Advanced Engineering Mathematics

10th Edition

ISBN:9780470458365

Author:Erwin Kreyszig

Publisher:Erwin Kreyszig

Chapter2: Second-order Linear Odes

Section: Chapter Questions

Problem 1RQ

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Question

Situation 3 (Items 48-49). The composite shaft, consisting of aluminum, copper, and steel sections, is subject to the loading shown in Figure 3. Determine the following: 49. The displacement of end A with respect to end D. A. -0.003414 in. B. 0.00934 in. C. -0.00122 in. D. 0,00157 in.

Aluminum
Eal = 10(10³) ksi
AAB=0.09 in²
2.00 kip
A
Copper
Ecu=18(10³) ksi
ABC = 0.12 in²
-18 in.-
B
3.50 kip
3.50 kip
12 in.
Figure 3
Steel
Est=29(10³) ksi
ACD = 0.06 in²
1.75 kip
1.75 kip
16 in-
1.50 kip
D

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