Also deduce the Jacobi identity for the cross product: u × (v × w) +w × (u × v) +v × (w x u) = 0 их

Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
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Chapter2: Second-order Linear Odes
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fron Naive Lie theory (John Stillwell)

Need help with attached highligted 1.4.4

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Exercises
The cross product is an operation on Ri+Rj+Rk because u x v is in Ri+Rj+Rk
for any u, v E Ri+Rj+Rk. However, it is neither a commutative nor associative
operation, as Exercises 1.4.1 and 1.4.3 show.
1.4.1 Prove the antisymmetric property u × v = –v × u.
1.4.2 Prove that u × (v × w) = v(u ·w) – w(u ·v) for pure imaginary u, v, w.
1.4.3 Deduce from Exercise 1.4.2 that x is not associative.
1.4.4 Also deduce the Jacobi identity for the cross product:
их (vx w)+wx (ихv) +vx (wx
х и) — 0.
The antisymmetric and Jacobi properties show that the cross product is not com-
pletely lawless. These properties define what we later call a Lie algebra.
Transcribed Image Text:Exercises The cross product is an operation on Ri+Rj+Rk because u x v is in Ri+Rj+Rk for any u, v E Ri+Rj+Rk. However, it is neither a commutative nor associative operation, as Exercises 1.4.1 and 1.4.3 show. 1.4.1 Prove the antisymmetric property u × v = –v × u. 1.4.2 Prove that u × (v × w) = v(u ·w) – w(u ·v) for pure imaginary u, v, w. 1.4.3 Deduce from Exercise 1.4.2 that x is not associative. 1.4.4 Also deduce the Jacobi identity for the cross product: их (vx w)+wx (ихv) +vx (wx х и) — 0. The antisymmetric and Jacobi properties show that the cross product is not com- pletely lawless. These properties define what we later call a Lie algebra.
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