Along the z-axis, indicated by the dashed line on this diagram, the electric field is E = -Cz²2, where C is a positive constant. The minus sign implies the field points backwards. A particle of charge +9o and mass m is released from rest from z = on the z-axis. a) What is the particle's speed when it reaches z = and zo- %3D +20, 0? Answer in terms of qo, m, C, b) At z 0, what is the particle's acceleration?

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Chapter1: Units, Trigonometry. And Vectors
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Along the z-axis, indicated by the dashed line on this diagram, the electric field is
E = -Cz²2, where C is a positive constant. The minus sign implies the field points
backwards. A particle of charge +q and mass m is released from rest from z =
on the z-axis.
a) What is the particle's speed when it reaches z = 0? Answer in terms of qo, m, C,
and zo-
+%o,
b) At z = 0, what is the particle's acceleration?
z = 0
Transcribed Image Text:Along the z-axis, indicated by the dashed line on this diagram, the electric field is E = -Cz²2, where C is a positive constant. The minus sign implies the field points backwards. A particle of charge +q and mass m is released from rest from z = on the z-axis. a) What is the particle's speed when it reaches z = 0? Answer in terms of qo, m, C, and zo- +%o, b) At z = 0, what is the particle's acceleration? z = 0
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