Allen's hummingbird (Selasphorus sasin) has been studied by zoologist Bill Alther.+ Suppose a small group of 13 Allen's hummingbirds has been under study in Arizona. The average weight for these birds is x = 3.15 grams. Based on previous studies, we can assume that the weights of Allen's hummingbirds have a normal distribution, with = 0.28 gram. When finding an 80% confidence interval, what is the critical value for confidence level? (Give your answer to two decimal places.) Zc = 1.28 (a) Find an 80% confidence interval for the average weights of Allen's hummingbirds in the study region. What is the margin of error? (Round your answers to two decimal places.) lower limit upper limit margin of error ✔a is unknown Oσ is known On is large (b) What conditions are necessary for your calculations? (Select all that apply.) O uniform distribution of weights normal distribution of weights (c) Interpret your results in the context of this problem. O We are 20% confident that the true average weight of Allen's hummingbirds falls within this interval. O We are 80% confident that the true average weight of Allen's hummingbirds falls within this interval. O The probability that this interval contains the true average weight of Allen's hummingbirds is 0.20. O The probability that this interval contains the true average weight of Allen's hummingbirds is 0.80. On= 3.05 3.25 (d) Which equation is used to find the sample size n for estimating when is known? n = (²-²)² -√2/0 0.10 On= On= On= - (²00) ² Find the sample size necessary for an 80% confidence level with a maximal margin of error E = 0.16 for the mean weights of the hummingbirds. (Round up to the nearest whole number.) hummingbirds
Allen's hummingbird (Selasphorus sasin) has been studied by zoologist Bill Alther.+ Suppose a small group of 13 Allen's hummingbirds has been under study in Arizona. The average weight for these birds is x = 3.15 grams. Based on previous studies, we can assume that the weights of Allen's hummingbirds have a normal distribution, with = 0.28 gram. When finding an 80% confidence interval, what is the critical value for confidence level? (Give your answer to two decimal places.) Zc = 1.28 (a) Find an 80% confidence interval for the average weights of Allen's hummingbirds in the study region. What is the margin of error? (Round your answers to two decimal places.) lower limit upper limit margin of error ✔a is unknown Oσ is known On is large (b) What conditions are necessary for your calculations? (Select all that apply.) O uniform distribution of weights normal distribution of weights (c) Interpret your results in the context of this problem. O We are 20% confident that the true average weight of Allen's hummingbirds falls within this interval. O We are 80% confident that the true average weight of Allen's hummingbirds falls within this interval. O The probability that this interval contains the true average weight of Allen's hummingbirds is 0.20. O The probability that this interval contains the true average weight of Allen's hummingbirds is 0.80. On= 3.05 3.25 (d) Which equation is used to find the sample size n for estimating when is known? n = (²-²)² -√2/0 0.10 On= On= On= - (²00) ² Find the sample size necessary for an 80% confidence level with a maximal margin of error E = 0.16 for the mean weights of the hummingbirds. (Round up to the nearest whole number.) hummingbirds
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
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