all V R sine sine Let the voltage source be 202135, the current source be 10245 and the impedance of the inductor be j50 ohm. The value of R for which the phase angle of the current through it is 90 degrees is ohm The power dissipated in the resistor is Watt
all V R sine sine Let the voltage source be 202135, the current source be 10245 and the impedance of the inductor be j50 ohm. The value of R for which the phase angle of the current through it is 90 degrees is ohm The power dissipated in the resistor is Watt
Delmar's Standard Textbook Of Electricity
7th Edition
ISBN:9781337900348
Author:Stephen L. Herman
Publisher:Stephen L. Herman
Chapter21: Resistive-capacitive Series Circuits
Section: Chapter Questions
Problem 6RQ: A 15-F AC capacitor is connected in series with a 50 resistor. The capacitor has a voltage rating...
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Question
![L
V
R
sine
sine
Let the voltage source be 202135, the current source be 10-45 and the impedance of the inductor be j50 ohm.
The value of R for which the phase angle of the current through it is 90 degrees is
ohm
The power dissipated in the resistor is
Watt](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fd0e16c12-9436-4a0d-87d3-6ed9bbbe67a9%2F3b99a1d7-0226-4bda-a297-257f0dfff41c%2Femgpcg_processed.png&w=3840&q=75)
Transcribed Image Text:L
V
R
sine
sine
Let the voltage source be 202135, the current source be 10-45 and the impedance of the inductor be j50 ohm.
The value of R for which the phase angle of the current through it is 90 degrees is
ohm
The power dissipated in the resistor is
Watt
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