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All liquids evaporate to a certain extent. The pressure exerted by the gas phase in equilibrium with the liquid is called vapor pressure, Pvap. The vapor pressure of a particular substance is determined by the strength of the intermolecular forces. But for any given substance, the vapor pressure only changes with temperature. The Clausius-Clapeyron equation expresses the relationship between vapor pressure and cemperature: Part A Consider the following two substances and their vapor pressures at 298 K. Vapor pressure (mmHg) Substance A 275 B 459 () (뉴-) AHvap R In P2 = In P + Based on this information, compare the characteristics of the two substances. Drag each item to the appropriate bin. where P2 and P are the vapor pressures that correspond to temperatures T2 and T1, respectively, AHvap is the molar heat of vaporization, and R=8.3145 J/(mol - K) is the • View Available Hint(s) gas constant. Reset Help Is a gas at 300 mmHg Has weaker intermolecular forces Has a higher heat of vaporization Has a higher boiling point Substance A Substance B

All liquids evaporate to a certain extent. The pressure exerted by the gas phase in equilibrium with the liquid is called vapor pressure, Pvap. The vapor pressure of a particular substance is determined by the strength of the intermolecular forces. But for any given substance, the vapor pressure only changes with temperature. The Clausius-Clapeyron equation expresses the relationship between vapor pressure and cemperature: Part A Consider the following two substances and their vapor pressures at 298 K. Vapor pressure (mmHg) Substance A 275 B 459 () (뉴-) AHvap R In P2 = In P + Based on this information, compare the characteristics of the two substances. Drag each item to the appropriate bin. where P2 and P are the vapor pressures that correspond to temperatures T2 and T1, respectively, AHvap is the molar heat of vaporization, and R=8.3145 J/(mol - K) is the • View Available Hint(s) gas constant. Reset Help Is a gas at 300 mmHg Has weaker intermolecular forces Has a higher heat of vaporization Has a higher boiling point Substance A Substance B

Chemistry
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Please answer question 8 part A and B

All liquids evaporate to a certain extent. The pressure exerted by the gas phase in equilibrium with the liquid is called vapor pressure, Pvap. The Part A vapor pressure of a particular substance is determined by the strength of the intermolecular forces. But for any given substance, the vapor pressure only changes with temperature. The Clausius-Clapeyron equation expresses the relationship between vapor pressure and temperature: Consider the following two substances and their vapor pressures at 298 K. Vapor pressure (mmHg) Substance A 275 В 459 In P2 = In P1 + ΔΗvap 1 R T1 T2 Based on this information, compare the characteristics of the two substances. Drag each item to the appropriate bin. where P2 and P1 are the vapor pressures that correspond to temperatures T, and T1, respectively, AHvap is the molar heat of vaporization, and R = 8.3145 J/(mol · K) is the View Available Hint(s) gas constant. Help Reset Is a gas at 300 mmHg Has weaker intermolecular forces Has a higher heat of vaporization Has a higher boiling point Substance A Substance B
Transcribed Image Text:All liquids evaporate to a certain extent. The pressure exerted by the gas phase in equilibrium with the liquid is called vapor pressure, Pvap. The Part A vapor pressure of a particular substance is determined by the strength of the intermolecular forces. But for any given substance, the vapor pressure only changes with temperature. The Clausius-Clapeyron equation expresses the relationship between vapor pressure and temperature: Consider the following two substances and their vapor pressures at 298 K. Vapor pressure (mmHg) Substance A 275 В 459 In P2 = In P1 + ΔΗvap 1 R T1 T2 Based on this information, compare the characteristics of the two substances. Drag each item to the appropriate bin. where P2 and P1 are the vapor pressures that correspond to temperatures T, and T1, respectively, AHvap is the molar heat of vaporization, and R = 8.3145 J/(mol · K) is the View Available Hint(s) gas constant. Help Reset Is a gas at 300 mmHg Has weaker intermolecular forces Has a higher heat of vaporization Has a higher boiling point Substance A Substance B
Part B The vapor pressure of dichloromethane, CH2 Cl2, at 0°C is 134 mmHg. The normal boiling point of dichloromethane is 40. °C. Calculate its molar heat of vaporization. Express your answer to three significant figures and include the appropriate units. • View Available Hint(s) HẢ 6 ? AHvap Value Units
Transcribed Image Text:Part B The vapor pressure of dichloromethane, CH2 Cl2, at 0°C is 134 mmHg. The normal boiling point of dichloromethane is 40. °C. Calculate its molar heat of vaporization. Express your answer to three significant figures and include the appropriate units. • View Available Hint(s) HẢ 6 ? AHvap Value Units
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