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(Algebra: solve quadratic equations) The two roots of a quadratic equation ax? + bx + x = 0 can be obtained using the following formula: -b + VB - 4ac -b - Vb - 4ac and r2 2a 2a Write a function with the following header void solveQuadraticEquation(double a, double b, double c, double& discriminant, double& rl, double& r2) b² - 4ac is called the discriminant of the quadratic equation. If the discriminant is less than 0, the equation has no roots. In this case, ignore the value in rl and r2. Write a test program that prompts the user to enter values for a, b, and c and dis- plays the result based on the discriminant. If the discriminant is greater than or equal to 0, display the two roots. If the discriminant is equal to 0, display the one root. Otherwise, display "the equation has no roots". See Programming Exercise 3.1 for sample runs.

(Algebra: solve quadratic equations) The two roots of a quadratic equation ax? + bx + x = 0 can be obtained using the following formula: -b + VB - 4ac -b - Vb - 4ac and r2 2a 2a Write a function with the following header void solveQuadraticEquation(double a, double b, double c, double& discriminant, double& rl, double& r2) b² - 4ac is called the discriminant of the quadratic equation. If the discriminant is less than 0, the equation has no roots. In this case, ignore the value in rl and r2. Write a test program that prompts the user to enter values for a, b, and c and dis- plays the result based on the discriminant. If the discriminant is greater than or equal to 0, display the two roots. If the discriminant is equal to 0, display the one root. Otherwise, display "the equation has no roots". See Programming Exercise 3.1 for sample runs.

Database System Concepts
Database System Concepts
7th Edition
ISBN:9780078022159
Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Chapter1: Introduction
Section: Chapter Questions
Problem 1PE
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(Algebra: solve quadratic equations) The two roots of a quadratic equation ax? + bx + x = 0 can be obtained using the following formula: -b + VB - 4ac -b - Vb - 4ac and r2 2a 2a Write a function with the following header void solveQuadraticEquation(double a, double b, double c, double& discriminant, double& rl, double& r2) b² - 4ac is called the discriminant of the quadratic equation. If the discriminant is less than 0, the equation has no roots. In this case, ignore the value in rl and r2. Write a test program that prompts the user to enter values for a, b, and c and dis- plays the result based on the discriminant. If the discriminant is greater than or equal to 0, display the two roots. If the discriminant is equal to 0, display the one root. Otherwise, display "the equation has no roots". See Programming Exercise 3.1 for sample runs.
Transcribed Image Text:(Algebra: solve quadratic equations) The two roots of a quadratic equation ax? + bx + x = 0 can be obtained using the following formula: -b + VB - 4ac -b - Vb - 4ac and r2 2a 2a Write a function with the following header void solveQuadraticEquation(double a, double b, double c, double& discriminant, double& rl, double& r2) b² - 4ac is called the discriminant of the quadratic equation. If the discriminant is less than 0, the equation has no roots. In this case, ignore the value in rl and r2. Write a test program that prompts the user to enter values for a, b, and c and dis- plays the result based on the discriminant. If the discriminant is greater than or equal to 0, display the two roots. If the discriminant is equal to 0, display the one root. Otherwise, display "the equation has no roots". See Programming Exercise 3.1 for sample runs.
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