Certainly! Here's the transcribed text from the image formatted for an educational website: --- ### Doubling Time for Investments with Continuous Compounding **Problem 1:** Find the time it takes for $7,700 to double when invested at an annual interest rate of 1%, compounded continuously. **Solution:** \[ \boxed{} \] years --- **Problem 2:** Find the time it takes for $770,000 to double when invested at an annual interest rate of 1%, compounded continuously. **Solution:** \[ \boxed{} \] years --- **Instructions:** - Give your answers accurate to 4 decimal places. **Additional Resources:** - [Question Help](#) \[Video\] [Submit Question](#) --- The problems involve calculations using the formula for continuous compounding, which is derived from the formula: \[ A = Pe^{rt} \] where: - \( A \) is the amount of money accumulated after n years, including interest. - \( P \) is the principal amount (initial investment). - \( r \) is the annual interest rate (decimal). - \( t \) is the time in years. - \( e \) is Euler's number, approximately equal to 2.71828. For doubling, set \( A = 2P \) and solve for \( t \).
Certainly! Here's the transcribed text from the image formatted for an educational website: --- ### Doubling Time for Investments with Continuous Compounding **Problem 1:** Find the time it takes for $7,700 to double when invested at an annual interest rate of 1%, compounded continuously. **Solution:** \[ \boxed{} \] years --- **Problem 2:** Find the time it takes for $770,000 to double when invested at an annual interest rate of 1%, compounded continuously. **Solution:** \[ \boxed{} \] years --- **Instructions:** - Give your answers accurate to 4 decimal places. **Additional Resources:** - [Question Help](#) \[Video\] [Submit Question](#) --- The problems involve calculations using the formula for continuous compounding, which is derived from the formula: \[ A = Pe^{rt} \] where: - \( A \) is the amount of money accumulated after n years, including interest. - \( P \) is the principal amount (initial investment). - \( r \) is the annual interest rate (decimal). - \( t \) is the time in years. - \( e \) is Euler's number, approximately equal to 2.71828. For doubling, set \( A = 2P \) and solve for \( t \).
Algebra and Trigonometry (6th Edition)
6th Edition
ISBN:9780134463216
Author:Robert F. Blitzer
Publisher:Robert F. Blitzer
ChapterP: Prerequisites: Fundamental Concepts Of Algebra
Section: Chapter Questions
Problem 1MCCP: In Exercises 1-25, simplify the given expression or perform the indicated operation (and simplify,...
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![Certainly! Here's the transcribed text from the image formatted for an educational website:
---
### Doubling Time for Investments with Continuous Compounding
**Problem 1:**
Find the time it takes for $7,700 to double when invested at an annual interest rate of 1%, compounded continuously.
**Solution:**
\[ \boxed{} \] years
---
**Problem 2:**
Find the time it takes for $770,000 to double when invested at an annual interest rate of 1%, compounded continuously.
**Solution:**
\[ \boxed{} \] years
---
**Instructions:**
- Give your answers accurate to 4 decimal places.
**Additional Resources:**
- [Question Help](#) \[Video\]
[Submit Question](#)
---
The problems involve calculations using the formula for continuous compounding, which is derived from the formula:
\[ A = Pe^{rt} \]
where:
- \( A \) is the amount of money accumulated after n years, including interest.
- \( P \) is the principal amount (initial investment).
- \( r \) is the annual interest rate (decimal).
- \( t \) is the time in years.
- \( e \) is Euler's number, approximately equal to 2.71828.
For doubling, set \( A = 2P \) and solve for \( t \).](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F48574c8c-8b8f-49cc-8aac-f3f504b7bee4%2Ffe28ec92-b0da-4340-9377-c22a8d67855e%2Fxylutth.jpeg&w=3840&q=75)
Transcribed Image Text:Certainly! Here's the transcribed text from the image formatted for an educational website:
---
### Doubling Time for Investments with Continuous Compounding
**Problem 1:**
Find the time it takes for $7,700 to double when invested at an annual interest rate of 1%, compounded continuously.
**Solution:**
\[ \boxed{} \] years
---
**Problem 2:**
Find the time it takes for $770,000 to double when invested at an annual interest rate of 1%, compounded continuously.
**Solution:**
\[ \boxed{} \] years
---
**Instructions:**
- Give your answers accurate to 4 decimal places.
**Additional Resources:**
- [Question Help](#) \[Video\]
[Submit Question](#)
---
The problems involve calculations using the formula for continuous compounding, which is derived from the formula:
\[ A = Pe^{rt} \]
where:
- \( A \) is the amount of money accumulated after n years, including interest.
- \( P \) is the principal amount (initial investment).
- \( r \) is the annual interest rate (decimal).
- \( t \) is the time in years.
- \( e \) is Euler's number, approximately equal to 2.71828.
For doubling, set \( A = 2P \) and solve for \( t \).
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