### Graphing Systems of Inequalities The image presents a system of inequalities along with a graph that is meant to represent the solutions to the system. The system given is: 1. \(-2x + y \leq -4\) 2. \(-2x + 4y \geq -8\) #### Explanation of the Graph The graph shown is on a coordinate plane ranging from \(-7\) to \(7\) on both the x-axis and the y-axis. The grid lines are marked at integer values to help plot points and draw the boundary lines for the inequalities. - **First Inequality \(-2x + y \leq -4\):** - To graph, convert the inequality to the equation of a line: \(y = 2x - 4\). - Plot the line with \(y\)-intercept \(-4\) and slope \(2\) (rise over run is 2 units up for each unit right). - Shade the region below the line since the inequality is \(\leq\). - **Second Inequality \(-2x + 4y \geq -8\):** - Convert to the line equation: \(4y = 2x - 8\) or \(y = \frac{1}{2}x - 2\). - Plot the line with \(y\)-intercept \(-2\) and slope \(\frac{1}{2}\) (rise 1 unit for every 2 units right). - Shade the region above the line since the inequality is \(\geq\). #### Intersection of the Regions The solution to the system of inequalities is the region where the shaded areas overlap. This represents all the pairs \((x, y)\) that satisfy both inequalities simultaneously. Feel free to experiment with different values of \(x\) to verify their positions relative to the boundary lines and identify suitable \(y\) values that satisfy each inequality.

Algebra and Trigonometry (6th Edition)
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Author:Robert F. Blitzer
Publisher:Robert F. Blitzer
ChapterP: Prerequisites: Fundamental Concepts Of Algebra
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Problem 1MCCP: In Exercises 1-25, simplify the given expression or perform the indicated operation (and simplify,...
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### Graphing Systems of Inequalities

The image presents a system of inequalities along with a graph that is meant to represent the solutions to the system. The system given is:

1. \(-2x + y \leq -4\)
2. \(-2x + 4y \geq -8\)

#### Explanation of the Graph

The graph shown is on a coordinate plane ranging from \(-7\) to \(7\) on both the x-axis and the y-axis. The grid lines are marked at integer values to help plot points and draw the boundary lines for the inequalities.

- **First Inequality \(-2x + y \leq -4\):** 
  - To graph, convert the inequality to the equation of a line: \(y = 2x - 4\).
  - Plot the line with \(y\)-intercept \(-4\) and slope \(2\) (rise over run is 2 units up for each unit right).
  - Shade the region below the line since the inequality is \(\leq\).

- **Second Inequality \(-2x + 4y \geq -8\):**
  - Convert to the line equation: \(4y = 2x - 8\) or \(y = \frac{1}{2}x - 2\).
  - Plot the line with \(y\)-intercept \(-2\) and slope \(\frac{1}{2}\) (rise 1 unit for every 2 units right).
  - Shade the region above the line since the inequality is \(\geq\).

#### Intersection of the Regions

The solution to the system of inequalities is the region where the shaded areas overlap. This represents all the pairs \((x, y)\) that satisfy both inequalities simultaneously. 

Feel free to experiment with different values of \(x\) to verify their positions relative to the boundary lines and identify suitable \(y\) values that satisfy each inequality.
Transcribed Image Text:### Graphing Systems of Inequalities The image presents a system of inequalities along with a graph that is meant to represent the solutions to the system. The system given is: 1. \(-2x + y \leq -4\) 2. \(-2x + 4y \geq -8\) #### Explanation of the Graph The graph shown is on a coordinate plane ranging from \(-7\) to \(7\) on both the x-axis and the y-axis. The grid lines are marked at integer values to help plot points and draw the boundary lines for the inequalities. - **First Inequality \(-2x + y \leq -4\):** - To graph, convert the inequality to the equation of a line: \(y = 2x - 4\). - Plot the line with \(y\)-intercept \(-4\) and slope \(2\) (rise over run is 2 units up for each unit right). - Shade the region below the line since the inequality is \(\leq\). - **Second Inequality \(-2x + 4y \geq -8\):** - Convert to the line equation: \(4y = 2x - 8\) or \(y = \frac{1}{2}x - 2\). - Plot the line with \(y\)-intercept \(-2\) and slope \(\frac{1}{2}\) (rise 1 unit for every 2 units right). - Shade the region above the line since the inequality is \(\geq\). #### Intersection of the Regions The solution to the system of inequalities is the region where the shaded areas overlap. This represents all the pairs \((x, y)\) that satisfy both inequalities simultaneously. Feel free to experiment with different values of \(x\) to verify their positions relative to the boundary lines and identify suitable \(y\) values that satisfy each inequality.
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