Find (if possible) a. AB and b. BA, if A = 1 −2 5 3 −4 4 4 4 −2 and B = 4 5 4 2 1 0 1 −2 4 .
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Find (if possible) a. AB and b. BA, if
| 1 | −2 | 5 |
| 3 | −4 | 4 |
| 4 | 4 | −2 |
and
| 4 | 5 | 4 |
| 2 | 1 | 0 |
| 1 | −2 | 4 |
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- Vector B→B→ has magnitude 7.30 and direction 14.0° below the +x-axis. Vector C→C→ has x-component Cx = −2.00 and y-component Cy = −6.70. a. What is the x-component of B→B→ ? b.What is the y-component of B→B→ ? c. What is the magnitude of C→C→ ? d. What angle does C→C→ make with the +x-axis in counterclockwise direction? A positive angle is counterclockwise from the +x-axis anwer in degrees e. What is the magnitude of C→+B→C→+B→ ? f. What angle does the resultant vector C→+B→C→+B→ make with the +x-axis in clockwise direction? A positive angle is counterclockwise from the +x-axis. asnwer in degrees g. What is the magnitude of C→−B→C→-B→ ? h. What angle does the vector C→−B→C→-B→ make with the +x-axis in counterclockwise direction? A positive angle is counterclockwise from the +x-axis. asnwer in degrees i. What is the x-component of C→−B→C→-B→ ? j.What is the y-component of C→−B→C→-B→ ?What is the x-component and magnitude of A→?The figure shows three vectors. Vector A→ has a length of 35.0, vector B→ has a length of 69.0, and vector C→ has a length of 21.0. Solve the given equations. A→∙B→= ? B→∙(A→+C→)= ?
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