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**Solve for \( y \).** \[ 2(3y - 7) = 16 \] Simplify your answer as much as possible. \[ y = \underline{\hspace{1cm}} \] --- Explanation: This problem involves solving for the variable \( y \) in the equation \( 2(3y - 7) = 16 \). Follow these steps to find the value of \( y \): 1. **Distribute** the 2 through the parentheses: \[ 2 \times 3y - 2 \times 7 = 16 \] \[ 6y - 14 = 16 \] 2. **Isolate** the term with the variable by adding 14 to both sides of the equation: \[ 6y - 14 + 14 = 16 + 14 \] \[ 6y = 30 \] 3. **Solve** for \( y \) by dividing both sides by 6: \[ \frac{6y}{6} = \frac{30}{6} \] \[ y = 5 \] Thus, the solution is \( y = 5 \).

**Solve for \( y \).** \[ 2(3y - 7) = 16 \] Simplify your answer as much as possible. \[ y = \underline{\hspace{1cm}} \] --- Explanation: This problem involves solving for the variable \( y \) in the equation \( 2(3y - 7) = 16 \). Follow these steps to find the value of \( y \): 1. **Distribute** the 2 through the parentheses: \[ 2 \times 3y - 2 \times 7 = 16 \] \[ 6y - 14 = 16 \] 2. **Isolate** the term with the variable by adding 14 to both sides of the equation: \[ 6y - 14 + 14 = 16 + 14 \] \[ 6y = 30 \] 3. **Solve** for \( y \) by dividing both sides by 6: \[ \frac{6y}{6} = \frac{30}{6} \] \[ y = 5 \] Thus, the solution is \( y = 5 \).

Algebra and Trigonometry (6th Edition)
Algebra and Trigonometry (6th Edition)
6th Edition
ISBN:9780134463216
Author:Robert F. Blitzer
Publisher:Robert F. Blitzer
ChapterP: Prerequisites: Fundamental Concepts Of Algebra
Section: Chapter Questions
Problem 1MCCP: In Exercises 1-25, simplify the given expression or perform the indicated operation (and simplify,...
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**Solve for \( y \).** \[ 2(3y - 7) = 16 \] Simplify your answer as much as possible. \[ y = \underline{\hspace{1cm}} \] --- Explanation: This problem involves solving for the variable \( y \) in the equation \( 2(3y - 7) = 16 \). Follow these steps to find the value of \( y \): 1. **Distribute** the 2 through the parentheses: \[ 2 \times 3y - 2 \times 7 = 16 \] \[ 6y - 14 = 16 \] 2. **Isolate** the term with the variable by adding 14 to both sides of the equation: \[ 6y - 14 + 14 = 16 + 14 \] \[ 6y = 30 \] 3. **Solve** for \( y \) by dividing both sides by 6: \[ \frac{6y}{6} = \frac{30}{6} \] \[ y = 5 \] Thus, the solution is \( y = 5 \).
Transcribed Image Text:**Solve for \( y \).** \[ 2(3y - 7) = 16 \] Simplify your answer as much as possible. \[ y = \underline{\hspace{1cm}} \] --- Explanation: This problem involves solving for the variable \( y \) in the equation \( 2(3y - 7) = 16 \). Follow these steps to find the value of \( y \): 1. **Distribute** the 2 through the parentheses: \[ 2 \times 3y - 2 \times 7 = 16 \] \[ 6y - 14 = 16 \] 2. **Isolate** the term with the variable by adding 14 to both sides of the equation: \[ 6y - 14 + 14 = 16 + 14 \] \[ 6y = 30 \] 3. **Solve** for \( y \) by dividing both sides by 6: \[ \frac{6y}{6} = \frac{30}{6} \] \[ y = 5 \] Thus, the solution is \( y = 5 \).
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