The image contains two mathematical equations labeled with numbers. Each equation involves square roots and variables. **Equation 14:** \[ \sqrt{3k - 64} = \sqrt{\frac{k}{3}} \] This equation involves two square root expressions set equal to each other. On the left, the expression under the square root is \(3k - 64\). On the right, the expression is \(\frac{k}{3}\). **Equation 16:** \[ n = 7 + \sqrt{-4n + 28} \] This equation is set in terms of \(n\). On the right side, it involves adding 7 to the square root of the expression \(-4n + 28\). These equations are designed to be solved for the variables \(k\) and \(n\), respectively. When solving, consider checking for any extraneous solutions that may result from the squaring process used to eliminate square roots.
The image contains two mathematical equations labeled with numbers. Each equation involves square roots and variables. **Equation 14:** \[ \sqrt{3k - 64} = \sqrt{\frac{k}{3}} \] This equation involves two square root expressions set equal to each other. On the left, the expression under the square root is \(3k - 64\). On the right, the expression is \(\frac{k}{3}\). **Equation 16:** \[ n = 7 + \sqrt{-4n + 28} \] This equation is set in terms of \(n\). On the right side, it involves adding 7 to the square root of the expression \(-4n + 28\). These equations are designed to be solved for the variables \(k\) and \(n\), respectively. When solving, consider checking for any extraneous solutions that may result from the squaring process used to eliminate square roots.
Algebra and Trigonometry (6th Edition)
6th Edition
ISBN:9780134463216
Author:Robert F. Blitzer
Publisher:Robert F. Blitzer
ChapterP: Prerequisites: Fundamental Concepts Of Algebra
Section: Chapter Questions
Problem 1MCCP: In Exercises 1-25, simplify the given expression or perform the indicated operation (and simplify,...
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![The image contains two mathematical equations labeled with numbers. Each equation involves square roots and variables.
**Equation 14:**
\[
\sqrt{3k - 64} = \sqrt{\frac{k}{3}}
\]
This equation involves two square root expressions set equal to each other. On the left, the expression under the square root is \(3k - 64\). On the right, the expression is \(\frac{k}{3}\).
**Equation 16:**
\[
n = 7 + \sqrt{-4n + 28}
\]
This equation is set in terms of \(n\). On the right side, it involves adding 7 to the square root of the expression \(-4n + 28\).
These equations are designed to be solved for the variables \(k\) and \(n\), respectively. When solving, consider checking for any extraneous solutions that may result from the squaring process used to eliminate square roots.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F8d59e81a-3610-4fe8-95bd-8152142fc5c0%2F5c5093c5-f2dc-45a3-b59b-7725efe005b2%2F7jnwnf.jpeg&w=3840&q=75)
Transcribed Image Text:The image contains two mathematical equations labeled with numbers. Each equation involves square roots and variables.
**Equation 14:**
\[
\sqrt{3k - 64} = \sqrt{\frac{k}{3}}
\]
This equation involves two square root expressions set equal to each other. On the left, the expression under the square root is \(3k - 64\). On the right, the expression is \(\frac{k}{3}\).
**Equation 16:**
\[
n = 7 + \sqrt{-4n + 28}
\]
This equation is set in terms of \(n\). On the right side, it involves adding 7 to the square root of the expression \(-4n + 28\).
These equations are designed to be solved for the variables \(k\) and \(n\), respectively. When solving, consider checking for any extraneous solutions that may result from the squaring process used to eliminate square roots.
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