**Problem Statement:** Find matrix \( B \) such that: \[ B^H B = A \] where: \[ A = \begin{bmatrix} 1 & -1 & 0 \\ -1 & 2 & -1 \\ 0 & -1 & 1 \end{bmatrix} \] --- **Explanation:** In this problem, you are asked to find a matrix \( B \) such that when you multiply it by its conjugate transpose \( B^H \), the result is matrix \( A \). The matrix \( A \) is a 3x3 Hermitian matrix, which means it is equal to its own conjugate transpose. This problem involves concepts from linear algebra related to matrix factorizations, particularly related to finding a factor of a Hermitian matrix.

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