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415 MID-YEAR TEST Multiple Choice (Part 1, page 2) NAME 2-1 12. The equation 15 %3D 12 -3 cleared of fractions is | 12. A. 12r - 75 = -3 B. 4r 25 = - 180 13. | C. 4r 25 = -3 D. r- 5 = – 180 -5 = - 14. 13. The solution of 3(x 5) – 2(3x – 3) = - 3(2 – x) is 15. 1. 3 16. A. B. -2 C. 2 D. | -- 17. 14. The solutions of x(4x - 5)(2x + 1) = 0 are 18. 5 1 D. 0, 4' 2 B. 0, 3 C. 0, 19. A. 1. 4. 2. 20. 15. The sum of two consecutive odd integers equals their difference cubed. Find the smaller of the two. 2-2 21. A. 121 B. 37 C. 21 D. 3 16. A rectangle is three times as long as it is wide. The perimeter is 40 feet. Find the width. A. 7 ft B. 15 ft C. 5 ft D. 12 ft 2-4 17. The solution of 10 3z < 4 is | 14 A. z < -2 B. z < 2 C. z > 2 18. The solution of 13 -3m < 2m – 7 is A. 5 < m B. 4 < m C. 4 > m D. m > 5 2-6 19. The solution of -5 1> 2-7 21. The solution of [3x - 7| < 9 is A. x < 3 B. - 3 x 10s 3. > x > 0 * Y 40 C10 X 100 3.

415 MID-YEAR TEST Multiple Choice (Part 1, page 2) NAME 2-1 12. The equation 15 %3D 12 -3 cleared of fractions is | 12. A. 12r - 75 = -3 B. 4r 25 = - 180 13. | C. 4r 25 = -3 D. r- 5 = – 180 -5 = - 14. 13. The solution of 3(x 5) – 2(3x – 3) = - 3(2 – x) is 15. 1. 3 16. A. B. -2 C. 2 D. | -- 17. 14. The solutions of x(4x - 5)(2x + 1) = 0 are 18. 5 1 D. 0, 4' 2 B. 0, 3 C. 0, 19. A. 1. 4. 2. 20. 15. The sum of two consecutive odd integers equals their difference cubed. Find the smaller of the two. 2-2 21. A. 121 B. 37 C. 21 D. 3 16. A rectangle is three times as long as it is wide. The perimeter is 40 feet. Find the width. A. 7 ft B. 15 ft C. 5 ft D. 12 ft 2-4 17. The solution of 10 3z < 4 is | 14 A. z < -2 B. z < 2 C. z > 2 18. The solution of 13 -3m < 2m – 7 is A. 5 < m B. 4 < m C. 4 > m D. m > 5 2-6 19. The solution of -5 1> 2-7 21. The solution of [3x - 7| < 9 is A. x < 3 B. - 3 x 10s 3. > x > 0 * Y 40 C10 X 100 3.

Algebra and Trigonometry (6th Edition)
Algebra and Trigonometry (6th Edition)
6th Edition
ISBN:9780134463216
Author:Robert F. Blitzer
Publisher:Robert F. Blitzer
ChapterP: Prerequisites: Fundamental Concepts Of Algebra
Section: Chapter Questions
Problem 1MCCP: In Exercises 1-25, simplify the given expression or perform the indicated operation (and simplify,...
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415 MID-YEAR TEST Multiple Choice (Part 1, page 2) NAME 2-1 12. The equation 15 %3D 12 -3 cleared of fractions is | 12. A. 12r - 75 = -3 B. 4r 25 = - 180 13. | C. 4r 25 = -3 D. r- 5 = – 180 -5 = - 14. 13. The solution of 3(x 5) – 2(3x – 3) = - 3(2 – x) is 15. 1. 3 16. A. B. -2 C. 2 D. | -- 17. 14. The solutions of x(4x - 5)(2x + 1) = 0 are 18. 5 1 D. 0, 4' 2 B. 0, 3 C. 0, 19. A. 1. 4. 2. 20. 15. The sum of two consecutive odd integers equals their difference cubed. Find the smaller of the two. 2-2 21. A. 121 B. 37 C. 21 D. 3 16. A rectangle is three times as long as it is wide. The perimeter is 40 feet. Find the width. A. 7 ft B. 15 ft C. 5 ft D. 12 ft 2-4 17. The solution of 10 3z < 4 is | 14 A. z < -2 B. z < 2 C. z > 2 18. The solution of 13 -3m < 2m – 7 is A. 5 < m B. 4 < m C. 4 > m D. m > 5 2-6 19. The solution of -5 <r + 3 <7 is A. -8 <r< 7 B. -8 <rs4 C. -8<ror r< 10 D. -8 <r and r< 10 | 20. The solution of 7 < 3 – 5t < 8 is A. -2 <t < - 1 B. -1<t < -2 C. 4. | >1> 2-7 21. The solution of [3x - 7| < 9 is A. x < 3 B. - 3 x 10s 3. > x > 0 * Y 40 C10 X 100 3.
Transcribed Image Text:415 MID-YEAR TEST Multiple Choice (Part 1, page 2) NAME 2-1 12. The equation 15 %3D 12 -3 cleared of fractions is | 12. A. 12r - 75 = -3 B. 4r 25 = - 180 13. | C. 4r 25 = -3 D. r- 5 = – 180 -5 = - 14. 13. The solution of 3(x 5) – 2(3x – 3) = - 3(2 – x) is 15. 1. 3 16. A. B. -2 C. 2 D. | -- 17. 14. The solutions of x(4x - 5)(2x + 1) = 0 are 18. 5 1 D. 0, 4' 2 B. 0, 3 C. 0, 19. A. 1. 4. 2. 20. 15. The sum of two consecutive odd integers equals their difference cubed. Find the smaller of the two. 2-2 21. A. 121 B. 37 C. 21 D. 3 16. A rectangle is three times as long as it is wide. The perimeter is 40 feet. Find the width. A. 7 ft B. 15 ft C. 5 ft D. 12 ft 2-4 17. The solution of 10 3z < 4 is | 14 A. z < -2 B. z < 2 C. z > 2 18. The solution of 13 -3m < 2m – 7 is A. 5 < m B. 4 < m C. 4 > m D. m > 5 2-6 19. The solution of -5 <r + 3 <7 is A. -8 <r< 7 B. -8 <rs4 C. -8<ror r< 10 D. -8 <r and r< 10 | 20. The solution of 7 < 3 – 5t < 8 is A. -2 <t < - 1 B. -1<t < -2 C. 4. | >1> 2-7 21. The solution of [3x - 7| < 9 is A. x < 3 B. - 3 x 10s 3. > x > 0 * Y 40 C10 X 100 3.
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