Alexander is looking up at a 45-foot tall building at an angle of elevation of 32°. If his eyes are approximately 6 feet from the ground, what is his horizontal distance from the building? Round your answer to the nearest hundredth. 45 ft 32° Hint: SOH-CAH-TOA (Refer to the "Trigonometry Anchor Chart" too). Don't forget to subtract to find the right side of the triangle!

Elementary Geometry For College Students, 7e
7th Edition
ISBN:9781337614085
Author:Alexander, Daniel C.; Koeberlein, Geralyn M.
Publisher:Alexander, Daniel C.; Koeberlein, Geralyn M.
ChapterP: Preliminary Concepts
SectionP.CT: Test
Problem 1CT
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Alexander is looking up at a 45-foot tall building at an angle of elevation of
32°. If his eyes are approximately 6 feet from the ground, what is his horizontal
distance from the building? Round your answer to the nearest hundredth.
-45 ft
32°
6 ft-
Hint: SOH-CAH-TOA (Refer to the "Trigonometry Anchor Chart" too). Don't forget
to subtract to find the right side of the triangle!
O 24.37 ft
O 62.41 ft
O 73.60 ft
Transcribed Image Text:Alexander is looking up at a 45-foot tall building at an angle of elevation of 32°. If his eyes are approximately 6 feet from the ground, what is his horizontal distance from the building? Round your answer to the nearest hundredth. -45 ft 32° 6 ft- Hint: SOH-CAH-TOA (Refer to the "Trigonometry Anchor Chart" too). Don't forget to subtract to find the right side of the triangle! O 24.37 ft O 62.41 ft O 73.60 ft
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