Alewuya invests a total of $24,500 in two accounts paying 2% and 12% simple interest, respectively. How much was invested in each account if, after one year, the total interest was $1,690.00. A) Enter an equation that uses the information as it is given that can be used to solve this problem. Use a as your variable to represent the amount of money invested in the account paying 2% simple interest. Equation: B) The answers are: S was invested at 2% and was invested at 12%. Question Help: Video Submit Question

Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
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Chapter2: Second-order Linear Odes
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**Problem Statement:**
Alewuya invests a total of $24,500 in two accounts paying 2% and 12% simple interest, respectively. How much was invested in each account if, after one year, the total interest was $1,690.00?

**Part A: Formulating the Equation**

*Task:* Enter an equation that uses the information as it is given that can be used to solve this problem. Use \( x \) as your variable to represent the amount of money invested in the account paying 2% simple interest.

*Equation:*
\[ x \times 0.02 + (24500 - x) \times 0.12 = 1690 \]

**Part B: Solving the Problem**

*Task:* Determine how much was invested in each account.

*The answers are:*
\[ \$ \_\_\_\_\_ \] was invested at 2% and
\[ \$ \_\_\_\_\_ \] was invested at 12%.

**Question Help:** 
[Video tutorial available]

**Submit Answer Button**

**Explanation of Symbols:**
- \( x \) is the amount of money invested in the account with 2% interest.
- \( 24500 - x \) is the amount of money invested in the account with 12% interest.
- The equation accounts for the sum of interests from both investments totaling $1,690.00 after one year. 

**Calculation Steps:**
1. Substitute the given values and solve the equation for \( x \).
2. Calculate the amounts invested at 2% and 12% interest respectively.
Transcribed Image Text:**Problem Statement:** Alewuya invests a total of $24,500 in two accounts paying 2% and 12% simple interest, respectively. How much was invested in each account if, after one year, the total interest was $1,690.00? **Part A: Formulating the Equation** *Task:* Enter an equation that uses the information as it is given that can be used to solve this problem. Use \( x \) as your variable to represent the amount of money invested in the account paying 2% simple interest. *Equation:* \[ x \times 0.02 + (24500 - x) \times 0.12 = 1690 \] **Part B: Solving the Problem** *Task:* Determine how much was invested in each account. *The answers are:* \[ \$ \_\_\_\_\_ \] was invested at 2% and \[ \$ \_\_\_\_\_ \] was invested at 12%. **Question Help:** [Video tutorial available] **Submit Answer Button** **Explanation of Symbols:** - \( x \) is the amount of money invested in the account with 2% interest. - \( 24500 - x \) is the amount of money invested in the account with 12% interest. - The equation accounts for the sum of interests from both investments totaling $1,690.00 after one year. **Calculation Steps:** 1. Substitute the given values and solve the equation for \( x \). 2. Calculate the amounts invested at 2% and 12% interest respectively.
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