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ake a change of variable, x= Py, that transforms the quadratic form 5x2 + 16x₁x₂ + 5x2 into a quadratic form with no cross-product term. Give P and the new quadratic form. Which of the following matrices can be used as P in x = Py to produce a quadratic form with no cross product term? A. -|-| -|-| 1 1 √2 √2 1 1 √2 √2 he corresponding quadratic form is y Dy= Simplify your answer.) OB. 1 √√2 1 √√2 -|-| 1 1 O C. -- -|-| 1 1 1 1 √2 √2 O D. - The

ake a change of variable, x= Py, that transforms the quadratic form 5x2 + 16x₁x₂ + 5x2 into a quadratic form with no cross-product term. Give P and the new quadratic form. Which of the following matrices can be used as P in x = Py to produce a quadratic form with no cross product term? A. -|-| -|-| 1 1 √2 √2 1 1 √2 √2 he corresponding quadratic form is y Dy= Simplify your answer.) OB. 1 √√2 1 √√2 -|-| 1 1 O C. -- -|-| 1 1 1 1 √2 √2 O D. - The

Algebra & Trigonometry with Analytic Geometry
Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter4: Polynomial And Rational Functions
Section4.3: Zeros Of Polynomials
Problem 35E
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Take a change of variable, x = Py, that transforms the quadratic form 5x2 +16x+x2+5x?into a quadratic form with no cross-product term. Give P and the new quadratic form. Which of the following matrices can be used as P in x = Py to produce a quadratic form with no cross product term? A. 1 存在 1 前一 5 1 1 2 The corresponding quadratic form is y' Dy=- Simplify your answer.) O B. 1 √√2 1 √√2 1 1 √2 √√2 ~ O C. 1 1 √2 √2 1 1 √2 √2 O D. 15 1 √√2 1 5 1 √√2 CS se
Transcribed Image Text:Take a change of variable, x = Py, that transforms the quadratic form 5x2 +16x+x2+5x?into a quadratic form with no cross-product term. Give P and the new quadratic form. Which of the following matrices can be used as P in x = Py to produce a quadratic form with no cross product term? A. 1 存在 1 前一 5 1 1 2 The corresponding quadratic form is y' Dy=- Simplify your answer.) O B. 1 √√2 1 √√2 1 1 √2 √√2 ~ O C. 1 1 √2 √2 1 1 √2 √2 O D. 15 1 √√2 1 5 1 √√2 CS se
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