: Air undergoes a three-process cycle. For 2 kg of air if the processes are: 1 → 2: constant temperature expansion .2 → 3: constant volume. 3 → 1: constant- pressure compression .The necessary information is T1 = 100°C, T3 = 600°C, and P1 = 200 kPa. R= 0.287 KJ/Kg.k , Cp= 1.051 KJ/Kg.k , Cv= 0.764 KJ/Kg.k. pressure compression .The necessary information is T1= 100°C, T3 = 600°C, and P1 = 200 kPa. R= 0.287KJ/Kg.k, Cp= 1.051 KJ/Kg.k, Cv= 0.764 KJ/Kg.k.The work net is*2 pointsO 210O - 105O 105The work W31 is*1 point- 287 KJO 287 KJThe internal energy U31 is*1 point-764 KJ- 1051 KJ-967 KJThe heat transfer Q23 is *1 pointO 764 KJO - 764 KJThe heat transfer Q12 is *2 points182 kJ-282 kJThe heat transfer Q31 is *2 points- 1051 KJ- 287 KJO -764 KJO o oO o oO O O The work W23 is *2 points-230 KJO 230 KJThe internal energy U12 is *1 point105 KJO - 105 KJThe internal energy U23 is*2 points- 764 KJO 764 KJThe internal energy net is *2 pointsO 105 KJO -105 KJThe heat transfer net is *1 point105 KJO - 105 KJ210 KJThe work W12 is *1 pointO 287 kJO 182 kJO O OO O O

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Answered: Air undergoes a three-process cycle.…

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

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: Air undergoes a three-process cycle. For 2 kg of air if the processes are: 1 → 2: constant temperature expansion .2 → 3: constant volume. 3 → 1: constant- pressure compression .The necessary information is T1 = 100°C, T3 = 600°C, and P1 = 200 kPa. R= 0.287 KJ/Kg.k , Cp= 1.051 KJ/Kg.k , Cv= 0.764 KJ/Kg.k.

pressure compression .The necessary information is T1
= 100°C, T3 = 600°C, and P1 = 200 kPa. R= 0.287
KJ/Kg.k, Cp= 1.051 KJ/Kg.k, Cv= 0.764 KJ/Kg.k.
The work net is*
2 points
O 210
O - 105
O 105
The work W31 is*
1 point
- 287 KJ
O 287 KJ
The internal energy U31 is*
1 point
-764 KJ
- 1051 KJ
-967 KJ
The heat transfer Q23 is *
1 point
O 764 KJ
O - 764 KJ
The heat transfer Q12 is *
2 points
182 kJ
-282 kJ
The heat transfer Q31 is *
2 points
- 1051 KJ
- 287 KJ
O -764 KJ
O o o
O o o
O O O

The work W23 is *
2 points
-230 KJ
O 230 KJ
The internal energy U12 is *
1 point
105 KJ
O - 105 KJ
The internal energy U23 is*
2 points
- 764 KJ
O 764 KJ
The internal energy net is *
2 points
O 105 KJ
O -105 KJ
The heat transfer net is *
1 point
105 KJ
O - 105 KJ
210 KJ
The work W12 is *
1 point
O 287 kJ
O 182 kJ
O O O
O O O

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