please answer question ASAP II ReviewAir at a temperature of 80°F flows through the duct at Awith a velocity of 32 ft/s. (Figure 1)Part ADetermine the change in pressure between A and B. Account for the minor loss caused by the sudden change in diameterof the duct.Express your answer using three significant figures.V Αφ vec?рв — РА 3psiSubmitPrevious Answers Request AnswerFigure1 of 1>X Incorrect; Try Again; 4 attempts remaining18 in.( Return to AssignmentProvide Feedback6 in.

Given Data, DB= Diameter of section B = 18 in = 18/12 = 1.5 ft DA = Diameter of section A = 6 in = 6/12 = 0.5 ft VA = Velocity at A = 32 ft/s To determine, the pressure difference between A and B Pressure difference between A and B Since, both the pipes are connected in series, so, discharge at A = discharge at B π4xDA2xVA=π4xDB2xVB where, VB = Velocity at B 0.52 x32 = 1.52 xVB VB = 3.56 ft/s Neglecting the major losses, because of insufficient data to calculate the major loss. Considering only minor losses. The diameter is suddenly contracted between B and A. Hence, the sudden contraction loss is hcontraction = 0.5xVA22g hcontraction = 0.5x3222x32.174 = 7.96 ftApplying Bernoulli's equation between B and A PBρag+VB22g+ZB=PA2ρag+VA22g+ZA+hsudden where, ρa= Density of air = 0.0765 lb/ft3, PB and PA are the pressures at B and A, ZB and ZA are the datum head at B and A and, ZB=ZA Putting the values PBρag+3.5622x32.174=PAρag+3222x32.174+7.96 PB-PAρag=23.68 PB - PA = 23.68 x0.0765 x32.174 = 58.28 lbf/ft2 PB - PA = 58.28/144 = 0.4047 psi Thus, the change in pressure between B and A is 0.4047 psi

Answered: Air at a temperature of 80°F flows…

Engineering

Mechanical Engineering

Air at a temperature of 80°F flows through the duct at A with a velocity of 32 ft/s. (Figure 1)

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

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