Air as an ideal gas flows through the turbine and heat ex- changer arrangement shown in Fig. Data for the two flow streams are shown on the figure. Heat transfer to the sur- roundings can be neglected, as can all kinetic and potential en- ergy effects. Determine T3, in K, and the power output of the second turbine, in kW, at steady state. W11 = 10,000 kW W2 = ? Turbine Turbine 1 2 P3 = 4.5 bar T3 = ? T2 = 1100 K P2 = 5 bar T4 = 980 K P4 = 1 bar Air www twwww in 2 3 4 T = 1400 K P1 = 20 bar T5 = 1480 K 5 P5 = 1.35 bar ṁ3 = 1200 kg/min 6. Heat exchanger V T6 = 1200 K %3D P6 = 1 bar Air in

Elements Of Electromagnetics
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ISBN:9780190698614
Author:Sadiku, Matthew N. O.
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A quick solution without explanation, please, the solution is quick
* \Q1
Air as an ideal gas flows through the turbine and heat ex-
changer arrangement shown in Fig. Data for the two
flow streams are shown on the figure. Heat transfer to the sur-
roundings can be neglected, as can all kinetic and potential en-
ergy effects. Determine T3, in K, and the power output of the
second turbine, in kW, at steady state.
W11 = 10,000 kW
W12 = ?
Turbine
Turbine
1
P3 = 4.5 bar
T3 = ?
T2 = 1100 K
P2 = 5 bar
T4 = 980 K
P4 = 1 bar
wwww
wwww
Air
in
2
3
T = 1400 K
P1 = 20 bar
T5 = 1480 K
- 5 P5 = 1.35 bar
m3 = 1200 kg/min
Heat exchanger
V T6 = 1200 K
P6 = 1 bar
Air
in
Transcribed Image Text:* \Q1 Air as an ideal gas flows through the turbine and heat ex- changer arrangement shown in Fig. Data for the two flow streams are shown on the figure. Heat transfer to the sur- roundings can be neglected, as can all kinetic and potential en- ergy effects. Determine T3, in K, and the power output of the second turbine, in kW, at steady state. W11 = 10,000 kW W12 = ? Turbine Turbine 1 P3 = 4.5 bar T3 = ? T2 = 1100 K P2 = 5 bar T4 = 980 K P4 = 1 bar wwww wwww Air in 2 3 T = 1400 K P1 = 20 bar T5 = 1480 K - 5 P5 = 1.35 bar m3 = 1200 kg/min Heat exchanger V T6 = 1200 K P6 = 1 bar Air in
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