**Ages of Proofreaders**At a large publishing company, the mean age of proofreaders is 36.2 years and the standard deviation is 3.7 years. Assume the variable is normally distributed. Round intermediate z-value calculations to two decimal places and the final answers to at least four decimal places.**Part: 0 / 2****Part 1 of 2**If a proofreader from the company is randomly selected, find the probability that his or her age will be between 36 and 37.5 years.\[ P(36 < X < 37.5) = \][Input box with clear and reset buttons]There are no graphs or diagrams in the image. The content is mathematical and requests a probability calculation based on a normal distribution with given mean and standard deviation values.

Solution:Let X be the age of proof-readers.From the given information, X follows normal distribution…

Answered: Ages of Proofreaders At a large…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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Find the probability that x will be less than 30. Round the answer to at least four decimal places. The probability that x will be less than 30 is…
STATISTICS & PROBABILITY Direction: Solve the following problems. Round off your answer to two decimal places. Use the percentage form and include the percentage symbol (%) The length of time needed to do a particular activity is normally distributed with a mean of 2 hours and a standard deviation of 1.25 hours. What is the probability that a randomly selected student will spend 3.5 hours in doing the activity? The monthly food expenditure of a single person is 3000Php on average with a standard deviation of 300Php. Assuming that the monthly food expenditure is normally distributed, what percentage of these expenditures are between 2400Php and 4000Php? Find the area to the right of z = 1.37 Select one: A. 8.53% B. 43.45% C. 31.76% D. 47.88% Find the area between z = 0.46 and z = 2.56 Select one: A. 43.45% B. 31.76% C. 30.15% D. 97.98% Find the area between z = 0 and z = -2.03 Select one: A. 43.45% B. 47.88% C. 8.53% D. 31.76% Find the area to the left…
Subject : calculas
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A deviation score is the difference between the score and the __________.
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