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Again consider our example instruction set from class. Which of the following programs will encode this loop correctly? Assume that we have already set up the value of x is in register 1, the value of y is in register 2, and that pc = 0x20 before executing the first instruction below. i = -5 do { x += y i++ } while (i <= 0) OA. 60 05 6C 20 16 10 7C OB. 60 05 6C 24 16 10 7C OC. 60 FB 6C 20 16 10 73 OD. 60 FB 6C 24 16 10 73

Again consider our example instruction set from class. Which of the following programs will encode this loop correctly? Assume that we have already set up the value of x is in register 1, the value of y is in register 2, and that pc = 0x20 before executing the first instruction below. i = -5 do { x += y i++ } while (i <= 0) OA. 60 05 6C 20 16 10 7C OB. 60 05 6C 24 16 10 7C OC. 60 FB 6C 20 16 10 73 OD. 60 FB 6C 24 16 10 73

Computer Networking: A Top-Down Approach (7th Edition)
Computer Networking: A Top-Down Approach (7th Edition)
7th Edition
ISBN:9780133594140
Author:James Kurose, Keith Ross
Publisher:James Kurose, Keith Ross
Chapter1: Computer Networks And The Internet
Section: Chapter Questions
Problem R1RQ: What is the difference between a host and an end system? List several different types of end...
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Again consider our example instruction set from class. Which of the following programs will encode this loop correctly? Assume that we have already set up the value of x is in register 1, the value of y is in register 2, and that pc = 0x20 before executing the first instruction below. i = -5 do { X += y i++ } while (i <= 0) A. 60 05 6C 20 16 10 7C B. 60 05 6C 24 16 10 7C C. 60 FB 6C 20 16 10 73 D. 60 FB 6C 24 16 10 73
Transcribed Image Text:Again consider our example instruction set from class. Which of the following programs will encode this loop correctly? Assume that we have already set up the value of x is in register 1, the value of y is in register 2, and that pc = 0x20 before executing the first instruction below. i = -5 do { X += y i++ } while (i <= 0) A. 60 05 6C 20 16 10 7C B. 60 05 6C 24 16 10 7C C. 60 FB 6C 20 16 10 73 D. 60 FB 6C 24 16 10 73
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