After transforming AC sources to Phasors and representing passive components in impedance, the AC circuits are equivalent to DC circuits, since the voltage (in Phasor forms, V ), the current (in Phasor forms, I), and the impedance (Z) are related by a linear equation, i.e., V=I-Z. Thus, all DC circuit analysis methods are still applicable. Consider the circuit below, what is the voltage on the capacitor Ve? (Represent the result in ww the Polar form) + O 10/45° O 7.070°V O 8.75/30° O 15.25/67.78" V_s 10/45° R 100 Ω + Ve C -100jn

After transforming AC sources to Phasors and representing passive components in impedance, the AC circuits are equivalent to DC circuits, since the voltage (in Phasor forms, V ), the current (in Phasor forms, I), and the impedance (Z) are related by a linear equation, i.e., V=I-Z. Thus, all DC circuit analysis methods are still applicable. Consider the circuit below, what is the voltage on the capacitor Ve? (Represent the result in ww the Polar form) + O 10/45° O 7.070°V O 8.75/30° O 15.25/67.78" V_s 10/45° R 100 Ω + Ve C -100jn

Introductory Circuit Analysis (13th Edition)

13th Edition

ISBN:9780133923605

Author:Robert L. Boylestad

Publisher:Robert L. Boylestad

Chapter1: Introduction

Section: Chapter Questions

Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...

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Question

After transforming AC sources to Phasors and representing passive components in
impedance, the AC circuits are equivalent to DC circuits, since the voltage (in Phasor forms, V
), the current (in Phasor forms, I), and the impedance (Z) are related by a linear equation, i.e.,
V=I-Z
Thus, all DC circuit analysis methods are still applicable.
Consider the circuit below, what is the voltage on the capacitor V¿? (Represent the result in
ww
the Polar form)
O 10/45°
O 7.07/0°V
O 8.75/30°
O 15.25/67.78"
+
V_s
10/45°
R
100 Ω
+
V
C
-100jn

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