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After the jumper wire is connected across D2 in Step 3, what is the NEW potential of the high side of D2, relative to ground? Approximately 2.6V, because the forward voltage of the LED does not change. O Approximately +5V, because I am measuring to high potential instead of ground. Approximately +2.6V because nothing has changed in the circuit. 0.0 mV, because that location is now connected directly to ground.

After the jumper wire is connected across D2 in Step 3, what is the NEW potential of the high side of D2, relative to ground? Approximately 2.6V, because the forward voltage of the LED does not change. O Approximately +5V, because I am measuring to high potential instead of ground. Approximately +2.6V because nothing has changed in the circuit. 0.0 mV, because that location is now connected directly to ground.

Introductory Circuit Analysis (13th Edition)
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
Section: Chapter Questions
Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...
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STEP 3 Add a jumper wire to the circuit, in parallel with D2, as illustrated in this schematic: D1 R1 D2 Red 330 Q Blue PSB 5 V You will know it is connected correctly because D2 is shorted and goes out, causing D1 to become brighter. What will the voltage be across D2 now that it has been shorted? If there is no potential difference across D2, then it makes sense that no current will flow through it. • With the jumper connecting the high side of D2 directly to the breadboard ground rail, what will be the new potential of tha iunction point, relative to ground?
Transcribed Image Text:STEP 3 Add a jumper wire to the circuit, in parallel with D2, as illustrated in this schematic: D1 R1 D2 Red 330 Q Blue PSB 5 V You will know it is connected correctly because D2 is shorted and goes out, causing D1 to become brighter. What will the voltage be across D2 now that it has been shorted? If there is no potential difference across D2, then it makes sense that no current will flow through it. • With the jumper connecting the high side of D2 directly to the breadboard ground rail, what will be the new potential of tha iunction point, relative to ground?
After the jumper wire is connected across D2 in Step 3, what is the NEW potential of the high side of D2, relative to ground? Approximately 2.6V, because the forward voltage of the LED does not change. Approximately +5V, because I am measuring to high potential instead of ground. Approximately +2.6V because nothing has changed in the circuit. O 0.0 mV, because that location is now connected directly to ground.
Transcribed Image Text:After the jumper wire is connected across D2 in Step 3, what is the NEW potential of the high side of D2, relative to ground? Approximately 2.6V, because the forward voltage of the LED does not change. Approximately +5V, because I am measuring to high potential instead of ground. Approximately +2.6V because nothing has changed in the circuit. O 0.0 mV, because that location is now connected directly to ground.
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