After the execution of line 69 what happens to the offsets in ESP and EIP? 1READING CODE - STACK47list the output of the following program assuming the input is as follows:3101mov al, 0; Return code of 0mov ah, 4ch: Exit back to MSDOS4849423250int 21hMain ENDP548511752753Data; re-enter the data segment for this procedureinclude PCMAC.INC54NEWLINE EQU_PutCh 13, 10MessageSubMystery55DB 'Enter a number $'1056DW ?11MODEL SMALL5712STACK 100hDATACODE ; return to coding581359Messagel DB 'Total sold today, S'Message2 DB , is: $'Sublnput PROCmov cx, 4146015611662myLoop:1763CODEEXTERN GetDec: NEAR, PutDec NEARPutStr MessageSubcall GetDecadd Mystery, ax1864196520Main PROC66dec cxinz myLoopmov ax, Mystery21mov ax, @datads, axGetDatepush cxpush dxpush dxcall Sublnput send control to subproceduremov bx, axPutStr Messagel6722mov682369ret24702571Sublnput ENDP267273END Main; Tells where to start execution287475рop dxmov al, dhmov ah, 0call PutDecPutCh "pop dxmov al, dlmov ah, 0call PutDec76313233343536373839_PutCh "40рop сх41mov ax, cxcall PutDec_PutStr Message242434445mov ax, bxcall PutDecNEWLINE46

Answered: After the execution of line 69 what…

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After the execution of line 69 what happens to the offsets in ESP and EIP?

Database System Concepts

7th Edition

ISBN:9780078022159

Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Chapter1: Introduction

Section: Chapter Questions

Problem 1PE

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