After several iterations of the branch and bound algorithm applied to an integer program max cx subject to Ax≤ b, (3) EN² we obtain the diagram in Figure 2. Regarding the notations, N = {0, 1, 2,...}, A E R²x2, 6 € R², CE R2, z is the optimal value for each linear relaxation, and (x1, x2) is a corresponding solution. For Problem 2: of the form x₁≤6 z = 9₁ x₁ = 4.6 x ₁₂ = 3.9 2 Z=94 x₁ = 6₁20/₂=1 x2≤3 2 7=92 x₁ = 6.2,%₂2=3 x₁ = 7 z=as x₁ = 7, x₂ = 2.6 20274 z = 93 x ₂₁ = 5₁ x ₂ = 4 Figure 2: Branch and bound each question below, give values of a1, a2, a3, a4, a5 ER so that the diagram will satisfy the stated condition. If there are multiple values possible, then only one is sufficient. 1. (x1, x2)=(5, 4) is a solution to the integer program.
After several iterations of the branch and bound algorithm applied to an integer program max cx subject to Ax≤ b, (3) EN² we obtain the diagram in Figure 2. Regarding the notations, N = {0, 1, 2,...}, A E R²x2, 6 € R², CE R2, z is the optimal value for each linear relaxation, and (x1, x2) is a corresponding solution. For Problem 2: of the form x₁≤6 z = 9₁ x₁ = 4.6 x ₁₂ = 3.9 2 Z=94 x₁ = 6₁20/₂=1 x2≤3 2 7=92 x₁ = 6.2,%₂2=3 x₁ = 7 z=as x₁ = 7, x₂ = 2.6 20274 z = 93 x ₂₁ = 5₁ x ₂ = 4 Figure 2: Branch and bound each question below, give values of a1, a2, a3, a4, a5 ER so that the diagram will satisfy the stated condition. If there are multiple values possible, then only one is sufficient. 1. (x1, x2)=(5, 4) is a solution to the integer program.
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
Related questions
Question

Transcribed Image Text:After several iterations of the branch and bound algorithm applied to an integer program
max cx subject to
Ax≤ b,
(3)
XEN²
we obtain the diagram in Figure 2. Regarding the notations, N := {0, 1, 2,...}, A ɛ R²×², 6 ɛ R²,
CE R², z is the optimal value for each linear relaxation, and (x₁, x2) is a corresponding solution. For
Problem 2:
of the form
x₁≤6
ал
Z=
x₁ = 4.6 x ₁₂ = 3.9
Z=94
x₁ = 6₁ x ₂ = 1
2
x₂2 ≤3
Z=9₂
x₁₂₁= 6.2₁%₂2=3
x₁ = 7
21
>
z=as
x₁ = 7₁ x ₁₂ = 2.6
2
72274
z = 93
x ₁₂ = 5₁ x ₂₁ = 4
Figure 2: Branch and bound
each question below, give values of a₁, a2, a3, a4, a5 € R so that the diagram will satisfy the stated
condition. If there are multiple values possible, then only one is sufficient.
1. (x1, x2) = (5, 4) is a solution to the integer program.
2. (x₁, x₂) = (6, 1) is a solution to the integer program.
3. (x1, x₂) = (5, 4) could be a solution but (x₁, x2) = (6, 1) is not. In that case, what is the next step
of the branch and bound algorithm?
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