After finding the partial fraction decomposition, 10 x-6 -3x + 7 2 x + 3 + X 0 3x + 4 x² + 3 S + 7x²14x - 12 (x²+3)(x-6) dx 4 x-6 - dx = S

Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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After finding the partial fraction decomposition, 

\[
\int \frac{7x^2 - 14x - 12}{(x^2 + 3)(x - 6)} \, dx = \int
\]

An incorrect partial fraction decomposition is shown:

\[
\frac{10}{x-6} + \frac{-3x+7}{x^2+3} 
\]

This expression is marked incorrect with an "X".

The correct partial fraction decomposition is shown:

\[
\int \left(\frac{3x + 4}{x^2 + 3} + \frac{4}{x - 6}\right) \, dx
\]
Transcribed Image Text:After finding the partial fraction decomposition, \[ \int \frac{7x^2 - 14x - 12}{(x^2 + 3)(x - 6)} \, dx = \int \] An incorrect partial fraction decomposition is shown: \[ \frac{10}{x-6} + \frac{-3x+7}{x^2+3} \] This expression is marked incorrect with an "X". The correct partial fraction decomposition is shown: \[ \int \left(\frac{3x + 4}{x^2 + 3} + \frac{4}{x - 6}\right) \, dx \]
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